MySQL-对操作数使用集合差分时应包含1列

我有以下MYSQL查询工作：

SELECT 
    a.author_name, COUNT(*)
FROM
    publication p,
    authored a
WHERE
    a.pubkey = p.pubkey
        AND p.pubkey LIKE '%/asd/%'
GROUP BY a.author_name
HAVING COUNT(*) >= 1;

上面的查询是显示在包含“asd”一词的一本书中至少出版过一本书的作者的姓名

我的想法是这样做的设置差异。我试图通过使用以下sql语句找到尚未出版包含“asd”一词的书籍的作者：

SELECT 
    a.author_name
FROM
    author a,publication p
WHERE
   a.pubkey = p.pubkey AND a.author_name NOT IN (SELECT 
            a1.author_name, COUNT(*)
        FROM
            publication p1,
            author a1
        WHERE
            a1.pubkey = p1.pubkey
                AND p1.pubkey LIKE '%/asd/%'
        GROUP BY a1.author_name
        HAVING COUNT(*) >= 1);

但由于某些原因，我一直得到这个错误“操作数应该包含1列，我无法找到错误

---

谢谢。

尝试从内部查询中删除计数。可能是这样的

SELECT 
    a.author_name
FROM
    author a,publication p
WHERE
   a.pubkey = p.pubkey AND a.author_name NOT IN (SELECT 
            a1.author_name
        FROM
            publication p1,
            author a1
        WHERE
            a1.pubkey = p1.pubkey
                AND p1.pubkey LIKE '%/asd/%'
        GROUP BY a1.author_name
        HAVING COUNT(*) >= 1);

---

您应该能够在第一条SQL语句的WHERE子句中简单地使用NOT LIKE