Mysql 如何使用sQlite获取每个组的最大值，直到它返回到零

下表中有日期和价格字段。
价格从零开始，并可能随时间增加。
我想按该期间记录的最高价格分组，直到该值返回到零

+----------------+------------+
|      price     |    date    |
+----------------+------------+
|              6 | 2016-12-18 |
|              5 | 2016-12-17 |
|              4 | 2016-12-16 |
|              3 | 2016-12-15 |
|              2 | 2016-12-14 |
|              1 | 2016-12-13 |
|              0 | 2016-12-12 |
|              1 | 2016-12-11 |
|              0 | 2016-12-10 |
|              0 | 2016-12-09 |
|              5 | 2016-12-08 |
|              4 | 2016-12-07 |
|              3 | 2016-12-06 |
|              2 | 2016-12-05 |
|              1 | 2016-12-04 |
|              0 | 2016-12-03 |
|              1 | 2016-12-02 |
|              0 | 2016-12-01 |
|              2 | 2016-11-30 |
|              1 | 2016-11-29 |
+----------------+------------+

期望输出：

+----------------+------------+
|      price     |    date    |
+----------------+------------+
|              6 | 2016-12-18 |
|              1 | 2016-12-11 |
|              5 | 2016-12-08 |
|              1 | 2016-12-02 |
|              2 | 2016-11-30 |
+----------------+------------+

使用sQlite如何实现这一点

select      max(price)  as price
           ,max(date)   as date

from       (select      t1.price,t1.date,count(t2.date) as group_id

            from                    t t1

                        left join   t t2

                        on          t2.date <= t1.date
                                and t2.price = 0

            group by    t1.price,t1.date
            ) t

group by    group_id

having      max(price) <> 0

order by    date desc

+-------+------------+
| price | date       |
+-------+------------+
| 6     | 2016-12-18 |
+-------+------------+
| 1     | 2016-12-11 |
+-------+------------+
| 5     | 2016-12-08 |
+-------+------------+
| 1     | 2016-12-02 |
+-------+------------+
| 2     | 2016-11-30 |
+-------+------------+