Mysql 在where子句中选择别名

我在where子句中使用别名时遇到问题

我有这样的桌子：

我存储用户，他们可以互相发送消息。消息数据存储在social_Messages表中，包含核心用户、发送者和接收者ID

现在，当用户登录系统时，我只想显示与他/她进行对话的那些用户的列表

（已登录core_users.id为6） 我使用此查询并获取用户与之进行对话的朋友的ID：

SELECT
    messages.id,
    messages.status,
    messages.send_date,
    IF(
        core_users_sender = 6,
            core_users_receiver,
            core_users_sender
    ) as friend_id
FROM
    social_messages messages
WHERE
      messages.core_users_sender = 6
        OR
      messages.core_users_receiver = 6
GROUP BY
  friend_id

但问题是，当我尝试使用friend_id从core_users表中获取数据并使用query时：

SELECT
    messages.id,
    messages.status,
    messages.send_date,
    IF(
        core_users_sender = 6,
            core_users_receiver,
            core_users_sender
    ) as friend_id,
    users.fullname
FROM
    social_messages messages,
    core_users users
WHERE
      users.id = friend_id
      AND
      (
          messages.core_users_sender = 6
            OR
          messages.core_users_receiver = 6
      )
GROUP BY
  friend_id

---

我收到错误，因为在where子句中不能使用friend，因为它是在select中计算的您不能在

where

子句中使用别名。使用原始子查询

where users.id = IF(
                core_users_sender = 6,
                core_users_receiver,
                core_users_sender
        )

不允许在WHERE子句中引用列别名，因为在执行WHERE子句时可能尚未确定列值

---

不能在

where

子句中使用别名。使用原始子查询

where users.id = IF(
                core_users_sender = 6,
                core_users_receiver,
                core_users_sender
        )

不允许在WHERE子句中引用列别名，因为在执行WHERE子句时可能尚未确定列值

---

我建议您按以下方式重新排序查询：

SELECT
    messages.id,
    messages.status,
    messages.send_date,
    users.fullname,
    IF(
        messages.core_users_sender IS NOT NULL,
        messages.core_users_receiver,
        messages.core_users_sender
    ) as friend_id
FROM
    social_messages messages
    left join core_users users_sender
        on users_sender.id = messages.core_users_sender
        and messages.core_users_sender = 6
    left join core_users users_receiver
        on users_receiver.id = messages.core_users_receiver 
        and messages.core_users_receiver = 6

WHERE
    users_sender.id IS NOT NULL OR users_receiver.id IS NOT NULL

---

我建议您按以下方式重新排序查询：

SELECT
    messages.id,
    messages.status,
    messages.send_date,
    users.fullname,
    IF(
        messages.core_users_sender IS NOT NULL,
        messages.core_users_receiver,
        messages.core_users_sender
    ) as friend_id
FROM
    social_messages messages
    left join core_users users_sender
        on users_sender.id = messages.core_users_sender
        and messages.core_users_sender = 6
    left join core_users users_receiver
        on users_receiver.id = messages.core_users_receiver 
        and messages.core_users_receiver = 6

WHERE
    users_sender.id IS NOT NULL OR users_receiver.id IS NOT NULL

---

您可以为表添加别名并使用它

        SELECT messages.*, users.fullname
        FROM
        (SELECT
            messages.id,
            messages.status,
            messages.send_date,
            IF(
                core_users_sender = 6,
                    core_users_receiver,
                    core_users_sender
            ) as friend_id
        FROM
            social_messages messages
        WHERE
              messages.core_users_sender = 6
                OR
              messages.core_users_receiver = 6
        GROUP BY
          friend_id) as `messages`
        JOIN
              core_users users
        ON
              users.id = messages.friend_id

---

您可以为表添加别名并使用它

        SELECT messages.*, users.fullname
        FROM
        (SELECT
            messages.id,
            messages.status,
            messages.send_date,
            IF(
                core_users_sender = 6,
                    core_users_receiver,
                    core_users_sender
            ) as friend_id
        FROM
            social_messages messages
        WHERE
              messages.core_users_sender = 6
                OR
              messages.core_users_receiver = 6
        GROUP BY
          friend_id) as `messages`
        JOIN
              core_users users
        ON
              users.id = messages.friend_id