从Hibernate/MySQL调用存储过程：参数索引超出范围（3>；个参数，即2）

在使用MySQL db时，在Hibernate中调用insert存储过程时，我收到以下错误：

Hibernate: 
    { call InsertPayment(?, ?) }
sie 28, 2013 10:17:19 PM org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions
WARN: SQL Error: 0, SQLState: S1009
sie 28, 2013 10:17:19 PM org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions
ERROR: Parameter index out of range (3 > number of parameters, which is 2).
Exception in thread "main" org.hibernate.exception.GenericJDBCException: could not insert: [model_mapping_xml.TPayment]

CREATE PROCEDURE InsertPayment(
                    IN pIdAnother INT,  
                    IN pAmount DECIMAL(19,4)                                
                    )
BEGIN 
...       
END

MySQL数据库中的存储过程定义：

Hibernate: 
    { call InsertPayment(?, ?) }
sie 28, 2013 10:17:19 PM org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions
WARN: SQL Error: 0, SQLState: S1009
sie 28, 2013 10:17:19 PM org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions
ERROR: Parameter index out of range (3 > number of parameters, which is 2).
Exception in thread "main" org.hibernate.exception.GenericJDBCException: could not insert: [model_mapping_xml.TPayment]

CREATE PROCEDURE InsertPayment(
                    IN pIdAnother INT,  
                    IN pAmount DECIMAL(19,4)                                
                    )
BEGIN 
...       
END

TPayment.hbm.xml文件包含：

<sql-insert callable="true" check="none">
    { call InsertPayment(?, ?) }
</sql-insert>

为什么它会说“3>参数数量”，而该程序的每个地方都有2个参数？ （我可以用类似的方式调用deletePayment和modifyPayment存储过程，它们工作得很好…）

t付款映射：

<hibernate-mapping>
    <class name="model_mapping_xml.TPayment" table="TPayment" catalog="DB">
        <id name="idPayment" type="java.lang.Integer">
            <column name="IdPayment" />
            <generator class="identity" />
        </id>
        <version name="rowvers" type="timestamp" generated="always">
            <column name="Rowvers" length="19" not-null="true" />
        </version>
        <many-to-one name="another" class="model_mapping_xml.TAnother" fetch="select">
            <column name="IdAnother" not-null="true" />
        </many-to-one>
        <property name="amount" type="big_decimal">
            <column name="Amount" scale="4" not-null="true" />
        </property>
        <property name="date1" type="timestamp">
            <column name="Date1" length="19" not-null="false" />
        </property>
        <sql-insert callable="true" check="none">
            { call InsertPayment(?, ?) }
        </sql-insert>
        <sql-update callable="true" check="none">
            { call ModifyPayment(?, ?, ?, ?, ?) }
        </sql-update>
        <sql-delete callable="true" check="none">
            { call DeletePayment(?, ?) }
        </sql-delete>
    </class>
</hibernate-mapping>

{调用插入支付（？，）}
{呼叫修改支付（？，，，？，？）}
{调用DeletePayment（？，）}

其他映射：

<hibernate-mapping>
    <class name="model_mapping_xml.TAnother" table="TAnother" catalog="DB">
        <id name="idAnother" type="java.lang.Integer">
            <column name="IdAnother" />
            <generator class="identity" />
        </id>
        <property name="dateBegin" type="date">
            <column name="DateBegin" length="10" not-null="true" />
        </property>
        <property name="dateEnd" type="date">
            <column name="DateEnd" length="10" />
        </property>
        <property name="rowvers" type="timestamp">
            <column name="Rowvers" length="19" not-null="true" />
        </property>
        <set name="payment" table="TPayment" 
                inverse="true" lazy="true" fetch="select">
            <key>
                <column name="IdAnother" not-null="true" />
            </key>
            <one-to-many class="model_mapping_xml.TPayment" />
        </set>
    </class>
</hibernate-mapping>

post TPayment/TAnother定义，有时是一个与同一列映射到多个TimeUpdate定义相关的问题（这是xml映射，所以我想已经足够了）可能您缺少了一个与

TPayment.date1

columnHmm相关的

？

，但我在存储过程头中没有这个列（因为我不想让它出现在那里，date1是在存储过程中生成的，因此不需要通过参数传递它）。文档不是显式的，但我认为您不能只插入属性的子集，或者缺少如上所述的输出参数