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Mysql 如何从表中选择数据以转置或交叉表的方式获得输出?_Mysql_Case_Select Query - Fatal编程技术网

Mysql 如何从表中选择数据以转置或交叉表的方式获得输出?

Mysql 如何从表中选择数据以转置或交叉表的方式获得输出?,mysql,case,select-query,Mysql,Case,Select Query,我有一个表reportdata,其中包含以下值: reportdata memberCount monthname year Assigned user 588 February 2017 Assigned user 2 January 2017 Assigned user 22 May 2017 FHD

我有一个表reportdata,其中包含以下值:

 reportdata       memberCount     monthname     year
Assigned user        588           February     2017
Assigned user        2             January      2017
Assigned user        22            May          2017
FHD                  571           February     2017
FHD                  15            May          2017
ICM                  1             May          2017
sortingCompleted     1             February     2017
sortingCompleted     2             May          2017
我希望输出像:

   reportdata           January   February      May
    Assigned user           2       588          22
       FHD                  0       571          15
       ICM                  0        0            1
   sortingCompleted         0        1            2
我尝试了以下问题:

select d.reportdata,
CASE WHEN d.monthname='January' THEN d.MemberCount END AS January,
CASE WHEN d.monthname='February' THEN d.MemberCount END AS February,  
CASE WHEN d.monthname='May' THEN d.MemberCount END AS May from
(
select reportdata, memberCount,monthname
from cme_report where year='2017'
) as d

请建议获得预期输出的方法。感谢是预付款。

您可以尝试以下方法:

SELECT
    reportdata,
    SUM(CASE WHEN (monthname = 'January') THEN memberCount ELSE 0 END) AS 'January',
    SUM(CASE WHEN (monthname = 'February') THEN memberCount ELSE 0 END) AS 'February',
    SUM(CASE WHEN (monthname = 'May') THEN memberCount ELSE 0 END) AS 'May', 
FROM reportdata
WHERE year = '2017'
GROUP BY reportdata

非常感谢@Sebastian Brosch,这一切都很好。。。。。谢谢。。。。