编写mySQL以获取序列

我需要得到一个特定运动队的胜负顺序。例如：

表：结果

teamid    win  eventdate
======    ===  =========
1         0    26/01/2014
1         0    25/01/2014
2         1    26/01/2014
1         0    24/01/2014 
1         1    21/01/2014

---

它应该返回teamid 1有一个丢失的序列3。但是在sql中我怎么能做到这一点呢

MySQL不支持分析功能，但计算连续胜负的一种方法是：

此查询可作为执行进一步分析的基础。例如，要按团队获得最长的连胜和失利记录，请执行以下操作：

SELECT teamid, win, MAX(seq) FROM (
  SELECT   @seq    := IF(@teamid<=>teamid AND @win<=>win,@seq,0)+1 seq,
           @teamid := teamid teamid,
           @win    := win win
  FROM     RESULTS, (SELECT @teamid:=NULL, @win:=NULL) init
  ORDER BY teamid, STR_TO_DATE(eventdate, '%d/%m/%Y')
) t GROUP BY teamid, win

---

那么，如果第一队连续三次失利，接着是四场胜利，接着是两场失利，情况会怎样呢；第二队连续7胜8负？您希望得到什么样的结果？应该是order by eventdate，但这并不能回答问题。一队连输两场

SELECT teamid, win, MAX(seq) FROM (
  SELECT   @seq    := IF(@teamid<=>teamid AND @win<=>win,@seq,0)+1 seq,
           @teamid := teamid teamid,
           @win    := win win
  FROM     RESULTS, (SELECT @teamid:=NULL, @win:=NULL) init
  ORDER BY teamid, STR_TO_DATE(eventdate, '%d/%m/%Y')
) t GROUP BY teamid, win