Mysql 按标记名或资源名搜索资源

我已经用这个创建了一个搜索。一切都很顺利。我可以按名称搜索所有资源

如何按名称或具有该名称的标记搜索资源？

if I search for the word "Tutoring" in my text_field.

I should get all resources that contain the word "Tutoring" in the name, 
And all the resources that have the Tag "Tutoring".

Ex:

if I search for the word "Tutoring" in my text_field.

I should get all resources that contain the word "Tutoring" in the name, 
And all the resources that have the Tag "Tutoring".

我的当前代码一直出现此错误

Mysql2::Error: Column 'name' in where clause is ambiguous: 
SELECT COUNT(DISTINCT `resources`.`id`) FROM `resources` 
LEFT OUTER JOIN `resource_mappings` 
ON `resource_mappings`.`resource_id` = `resources`.`id` LEFT OUTER JOIN
`tags` ON `tags`.`id` = `resource_mappings`.`tag_id` WHERE (name like '%Tutoring%') 
AND (tags.name like '%Tutoring%')

模型

类资源

看起来属性

name

在您尝试访问的多个表中使用。您需要在

name

之前添加

table\u name.

，使其看起来像

WHERE（table\u name.name like…

）。只需将

table\u name

替换为要将名称与之进行比较的表和字段：-）

这就是我最后使用的代码

if name.present?    
  resources = resources.includes("tags").where("tags.name like :name OR resources.name like :name", {:name => "%#{name}%" })
end