mysql两个日期之间的天数按月分组_Mysql

mysql两个日期之间的天数按月分组

mysql

mysql两个日期之间的天数按月分组,mysql,Mysql,我试图将两个日期过滤器之间的日期按月分组。是否可以在mysql中执行此操作 Example : StartDate : 2012-01-19 EndDate: 2012-03-24 查询应返回按月份分组的天数 Jan : 19 Feb : 29 Mar :24 Apr : 0 May : 0 etc 有办法做到这一点吗谢谢此查询将在有限的日期范围内（过去100000天）对您有效。但更好的方法是使用WHILE循环编写单独的函数或过程 SELECT DATE_FORMAT(_date,

我试图将两个日期过滤器之间的日期按月分组。是否可以在mysql中执行此操作

Example : StartDate : 2012-01-19  EndDate: 2012-03-24

查询应返回按月份分组的天数

Jan : 19
Feb  : 29
Mar :24
Apr : 0
May : 0 etc

有办法做到这一点吗

谢谢

此查询将在有限的日期范围内（过去100000天）对您有效。但更好的方法是使用

WHILE

循环编写单独的函数或过程

SELECT DATE_FORMAT(_date, '%M') AS month,
       COUNT(1) AS days
FROM (
        SELECT CURDATE() - INTERVAL (a.a + (10 * b.a) + (100 * c.a) + (1000 * d.a) + (10000 * e.a)) DAY AS _date
        FROM (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS a
        CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS b
        CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS c
        CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS d
        CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS e
     ) a
WHERE _date BETWEEN '2012-01-19' AND '2012-03-24'
GROUP BY MONTH(_date)
ORDER BY MONTH(_date);

您在评论中的问题的新答案：我刚刚有一个问题，如何使用此查询连接到另一个表。基本思想是我有一个Bookings表，它有一个startDate和一个endDate，并使用这些作为_日期之间的参数，我需要找出每个月的天数。有没有关于我如何做到这一点的建议？还可以在单行而不是多行中返回结果：

见：

此查询将在有限的日期范围内（过去100000天）对您有效。但更好的方法是使用

WHILE

循环编写单独的函数或过程

SELECT DATE_FORMAT(_date, '%M') AS month,
       COUNT(1) AS days
FROM (
        SELECT CURDATE() - INTERVAL (a.a + (10 * b.a) + (100 * c.a) + (1000 * d.a) + (10000 * e.a)) DAY AS _date
        FROM (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS a
        CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS b
        CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS c
        CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS d
        CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS e
     ) a
WHERE _date BETWEEN '2012-01-19' AND '2012-03-24'
GROUP BY MONTH(_date)
ORDER BY MONTH(_date);

见：

如果您在所选答案中遇到问题，请尝试此选项，它非常适合MySQL 5.7+默认值：

SELECT
 YEAR(_date) AS year,
 MONTH(_date) AS month,
       COUNT(1) AS days
FROM (
        SELECT CURDATE() - INTERVAL (a.a + (10 * b.a) + (100 * c.a) + (1000 * d.a) + (10000 * e.a)) DAY AS _date
        FROM (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS a
        CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS b
        CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS c
        CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS d
        CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS e
     ) a
WHERE _date BETWEEN '2018-01-01' AND '2018-10-11'
GROUP BY YEAR(_date), MONTH(_date)
ORDER BY MONTH(_date);

如果您在所选答案中遇到问题，请尝试此选项，它非常适合MySQL 5.7+默认值：

SELECT
 YEAR(_date) AS year,
 MONTH(_date) AS month,
       COUNT(1) AS days
FROM (
        SELECT CURDATE() - INTERVAL (a.a + (10 * b.a) + (100 * c.a) + (1000 * d.a) + (10000 * e.a)) DAY AS _date
        FROM (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS a
        CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS b
        CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS c
        CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS d
        CROSS JOIN (SELECT 0 AS a UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS e
     ) a
WHERE _date BETWEEN '2018-01-01' AND '2018-10-11'
GROUP BY YEAR(_date), MONTH(_date)
ORDER BY MONTH(_date);

顺便问一下，2012年2月还有29天：）在我为您编写代码之前，您确定只想使用MySQL吗？因为如果你只计算月份的天数，你可以只使用PHP，而不使用MySQL。如果有什么方法可以确定你想要计算的确切天数，请在我给出解决方案之前告诉我。哦，是的，当然是2月29日：）不幸的是，我只需要使用MySql来计算，尽管这可能会让它有点复杂。我想知道我们是否可以使用GROUP BY，但问题是它只考虑开始日期的月份，而不考虑相应的月份。非常感谢您的帮助/建议。谢谢顺便问一下，2012年2月还有29天：）在我为您编写代码之前，您确定只想使用MySQL吗？因为如果你只计算月份的天数，你可以只使用PHP，而不使用MySQL。如果有什么方法可以确定你想要计算的确切天数，请在我给出解决方案之前告诉我。哦，是的，当然是2月29日：）不幸的是，我只需要使用MySql来计算，尽管这可能会让它有点复杂。我想知道我们是否可以使用GROUP BY，但问题是它只考虑开始日期的月份，而不考虑相应的月份。非常感谢您的帮助/建议。谢谢非常感谢！：）你说的有限日期工作是什么意思？它只适用于同一年内的日期吗？它只适用于过去1000天，但您可以将日期范围扩展到10000、100000，。。。只需再添加一个

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s就足够了。如果您得到了答案，请不要忘记接受最佳答案。我会这样做，因为它本身可以完美地工作。我有一个问题，如何使用此查询联接到另一个表。基本思想是我有一个Bookings表，它有一个startDate和一个endDate，并使用这些作为_日期之间的参数，我需要找出每个月的天数。有什么建议吗？是否可以在一行而不是多行中返回结果？谢谢！）你说的有限日期工作是什么意思？它只适用于同一年内的日期吗？它只适用于过去1000天，但您可以将日期范围扩展到10000、100000，。。。只需再添加一个

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