Mysql 报告所有可能的列组合_Mysql_Excel_Bash_Combinations_Summary

Mysql 报告所有可能的列组合

mysql excel bash

Mysql 报告所有可能的列组合,mysql,excel,bash,combinations,summary,Mysql,Excel,Bash,Combinations,Summary,我有一个关于组合的问题，但在一个相当复杂的情况下，我还没有找到任何帮助。我试图找到一种方法来报告数据集中所有可能的列组合该数据报告了土地变化的文献调查，并指出每篇文章中报告了哪些直接驱动因素和潜在驱动因素。因此，行表示单个项目，列表示所有近似和底层驱动程序。有六种类型的近似驱动因素和五种类型的基础驱动因素。对于每篇文章，在该文章中标识的驱动程序列中放置1，在未标识的驱动程序列中放置0。该表大致如下所示： key | d1 | d2 |...| d6 | i1 |...| i5 | ------

我有一个关于组合的问题，但在一个相当复杂的情况下，我还没有找到任何帮助。我试图找到一种方法来报告数据集中所有可能的列组合

该数据报告了土地变化的文献调查，并指出每篇文章中报告了哪些直接驱动因素和潜在驱动因素。因此，行表示单个项目，列表示所有近似和底层驱动程序。有六种类型的近似驱动因素和五种类型的基础驱动因素。对于每篇文章，在该文章中标识的驱动程序列中放置1，在未标识的驱动程序列中放置0。该表大致如下所示：

key | d1 | d2 |...| d6 | i1 |...| i5 |
--------------------------------------
A1  | 1  | 0  |...| 1  | 1  |...| 0  |
A2  | 0  | 1  |...| 0  | 0  |...| 1  |

其中A1条将d1和d6确定为直接驱动因素，i1确定为间接驱动因素，等等

我想做的是找出报告直接驱动因素、间接驱动因素以及直接和间接驱动因素的所有可能组合的文章数量。那么，例如，有多少物品标识d1、d2和i1；有多少个标识为d1、d2和i2；等等我的学生们把表格放在Excel文件中，我想Calc或Base可能有一个功能来自动化这个过程。有人知道我该怎么做吗

谢谢大家!

我最终放弃了，采取了暴力手段。我将该表导出为文本并将其拉入MySQL，然后使用bash脚本对选项进行迭代。如果其他人也有类似问题，下面是bash脚本：

    # Generate array containing factors
faclis1=( d_inf d_com d_inm d_ind d_agr d_bos i_dem i_eco i_tec i_pol i_cul );
#faclis=( "d_inf" "d_com" "d_inm" );
a=0
#echo ${faclis[@]};


# Remove output file if exists
if [ -e permcounts.txt ];
    then
    rm permcounts.txt;
    fi;

# Cycle through list of factors
for f1 in ${faclis1[@]};
do
# only proceed if factor not null
if [ ${f1} ];
then
# print remaining array just to be sure
echo "factor list is ${faclis1[@]}";
#echo ${faclis[@]};
echo "Now on factor ${f1}";
echo "FACTOR ${f1}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1;" metamorelia >> permcounts.txt;
# create sub array without current factor, 2 factors
faclis2=( ${faclis1[@]/${f1}/} );
#set sub-counter
b=0
#echo "${faclis2[@]}";
# loop through sub array, two factors
for f2 in ${faclis2[@]};
do
if [ ${f2} ] && \
[ "${f1}" != "${f2}" ];
then
echo "FACTOR ${f1} \
AND ${f2}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis3=( ${faclis2[@]//${f2}} );
c=0
#echo "${faclis3[@]}";
# loop through sub-array
for f3 in ${faclis3[@]};
do
if [ ${f3} ] && \
[ "${f1}" != "${f3}" ] && \
[ "${f2}" != "${f3}" ];

then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis4=( ${faclis3[@]//${f3}} );
d=0
#echo "${faclis4[@]}";
# loop through sub-array
for f4 in ${faclis4[@]};
do
if [ ${f4} ] && \
[ "${f1}" != "${f4}" ] && \
[ "${f2}" != "${f4}" ] && \
[ "${f3}" != "${f4}" ];
then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3} \
AND ${f4}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1 and \
${f4} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis5=( ${faclis4[@]//${f4}} );
e=0
#echo "${faclis5[@]}";
# loop through sub-array
for f5 in ${faclis5[@]};
do
if [ ${f5} ] && \
[ "${f1}" != "${f5}" ] && \
[ "${f2}" != "${f5}" ] && \
[ "${f3}" != "${f5}" ] && \
[ "${f4}" != "${f5}" ];
then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3} \
AND ${f4} \
AND ${f5}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1 and \
${f4} = 1 and \
${f5} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis6=( ${faclis5[@]//${f5}} );
f=0
#echo "${faclis6[@]}";
# loop through sub-array
for f6 in ${faclis6[@]};
do
if [ ${f6} ] && \
[ "${f1}" != "${f6}" ] && \
[ "${f2}" != "${f6}" ] && \
[ "${f3}" != "${f6}" ] && \
[ "${f4}" != "${f6}" ] && \
[ "${f5}" != "${f6}" ];
then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3} \
AND ${f4} \
AND ${f5} \
AND ${f6}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1 and \
${f4} = 1 and \
${f5} = 1 and \
${f6} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis7=( ${faclis6[@]//${f6}} );
g=0
#echo "${faclis7[@]}";
# loop through sub-array
for f7 in ${faclis7[@]};
do
if [ ${f7} ] && \
[ "${f1}" != "${f7}" ] && \
[ "${f2}" != "${f7}" ] && \
[ "${f3}" != "${f7}" ] && \
[ "${f4}" != "${f7}" ] && \
[ "${f5}" != "${f7}" ] && \
[ "${f6}" != "${f7}" ];
then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3} \
AND ${f4} \
AND ${f5} \
AND ${f6} \
AND ${f7}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1 and \
${f4} = 1 and \
${f5} = 1 and \
${f6} = 1 and \
${f7} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis8=( ${faclis7[@]//${f7}} );
h=0
#echo "${faclis8[@]}";
# loop through sub-array
for f8 in ${faclis8[@]};
do
if [ ${f8} ] && \
[ "${f1}" != "${f8}" ] && \
[ "${f2}" != "${f8}" ] && \
[ "${f3}" != "${f8}" ] && \
[ "${f4}" != "${f8}" ] && \
[ "${f5}" != "${f8}" ] && \
[ "${f6}" != "${f8}" ] && \
[ "${f7}" != "${f8}" ];
then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3} \
AND ${f4} \
AND ${f5} \
AND ${f6} \
AND ${f7} \
AND ${f8}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1 and \
${f4} = 1 and \
${f5} = 1 and \
${f6} = 1 and \
${f7} = 1 and \
${f8} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis9=( ${faclis8[@]//${f8}} );
i=0
#echo "${faclis9[@]}";
# loop through sub-array
for f9 in ${faclis9[@]};
do
if [ ${f9} ] && \
[ "${f1}" != "${f9}" ] && \
[ "${f2}" != "${f9}" ] && \
[ "${f3}" != "${f9}" ] && \
[ "${f4}" != "${f9}" ] && \
[ "${f5}" != "${f9}" ] && \
[ "${f6}" != "${f9}" ] && \
[ "${f7}" != "${f9}" ] && \
[ "${f8}" != "${f9}" ];
then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3} \
AND ${f4} \
AND ${f5} \
AND ${f6} \
AND ${f7} \
AND ${f8} \
AND ${f9}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1 and \
${f4} = 1 and \
${f5} = 1 and \
${f6} = 1 and \
${f7} = 1 and \
${f8} = 1 and \
${f9} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis10=( ${faclis9[@]//${f9}} );
j=0
#echo "${faclis10[@]}";
# loop through sub-array
for f10 in ${faclis10[@]};
do
if [ ${f10} ] && \
[ "${f1}" != "${f10}" ] && \
[ "${f2}" != "${f10}" ] && \
[ "${f3}" != "${f10}" ] && \
[ "${f4}" != "${f10}" ] && \
[ "${f5}" != "${f10}" ] && \
[ "${f6}" != "${f10}" ] && \
[ "${f7}" != "${f10}" ] && \
[ "${f8}" != "${f10}" ] && \
[ "${f9}" != "${f10}" ];
then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3} \
AND ${f4} \
AND ${f5} \
AND ${f6} \
AND ${f7} \
AND ${f8} \
AND ${f9} \
AND ${f10}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1 and \
${f4} = 1 and \
${f5} = 1 and \
${f6} = 1 and \
${f7} = 1 and \
${f8} = 1 and \
${f9} = 1 and \
${f10} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis11=( ${faclis10[@]//${f10}} );
k=0
#echo "${faclis11[@]}";
# loop through sub-array
for f11 in ${faclis11[@]};
do
if [ ${f11} ] && \
[ "${f1}" != "${f11}" ] && \
[ "${f2}" != "${f11}" ] && \
[ "${f3}" != "${f11}" ] && \
[ "${f4}" != "${f11}" ] && \
[ "${f5}" != "${f11}" ] && \
[ "${f6}" != "${f11}" ] && \
[ "${f7}" != "${f11}" ] && \
[ "${f8}" != "${f11}" ] && \
[ "${f9}" != "${f11}" ] && \
[ "${f10}" != "${f11}" ];
then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3} \
AND ${f4} \
AND ${f5} \
AND ${f6} \
AND ${f7} \
AND ${f8} \
AND ${f9} \
AND ${f10} \
AND ${f11}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1 and \
${f4} = 1 and \
${f5} = 1 and \
${f6} = 1 and \
${f7} = 1 and \
${f8} = 1 and \
${f9} = 1 and \
${f10} = 1 and \
${f11} = 1;" metamorelia >> permcounts.txt;

unset faclis11[k];
k=$((${k} + 1));
fi;
done;
unset faclis10[j];
j=$((${j} + 1));
fi;
done;
unset faclis9[i];
i=$((${i} + 1));
fi;
done;
unset faclis8[h];
h=$((${h} + 1));
fi;
done;
unset faclis7[g];
g=$((${g} + 1));
fi;
done;
unset faclis6[f];
f=$((${f} + 1));
fi;
done;
unset faclis5[e];
e=$((${e} + 1));
fi;
done;
unset faclis4[d];
d=$((${d} + 1));
fi;
done;
unset faclis3[c];
c=$((${c} + 1));
fi;
done;
# Remove analyzed factors from vector
unset faclis2[b];
b=$((${b} + 1));
fi;
done;
# remove nth item from array (progressively remove one item)
unset faclis1[a];
# increment n for next round
a=$((${a} + 1));
echo ${n};
fi;
done;

这个脚本有点低效，因为我认为我包含了很多不必要的操作，但它完成了任务。（我想是的。我的学生必须浏览输出文件，以确保所有内容都在那里。）

我最终放弃了，采用了蛮力方法。我将该表导出为文本并将其拉入MySQL，然后使用bash脚本对选项进行迭代。如果其他人也有类似问题，下面是bash脚本：

    # Generate array containing factors
faclis1=( d_inf d_com d_inm d_ind d_agr d_bos i_dem i_eco i_tec i_pol i_cul );
#faclis=( "d_inf" "d_com" "d_inm" );
a=0
#echo ${faclis[@]};


# Remove output file if exists
if [ -e permcounts.txt ];
    then
    rm permcounts.txt;
    fi;

# Cycle through list of factors
for f1 in ${faclis1[@]};
do
# only proceed if factor not null
if [ ${f1} ];
then
# print remaining array just to be sure
echo "factor list is ${faclis1[@]}";
#echo ${faclis[@]};
echo "Now on factor ${f1}";
echo "FACTOR ${f1}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1;" metamorelia >> permcounts.txt;
# create sub array without current factor, 2 factors
faclis2=( ${faclis1[@]/${f1}/} );
#set sub-counter
b=0
#echo "${faclis2[@]}";
# loop through sub array, two factors
for f2 in ${faclis2[@]};
do
if [ ${f2} ] && \
[ "${f1}" != "${f2}" ];
then
echo "FACTOR ${f1} \
AND ${f2}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis3=( ${faclis2[@]//${f2}} );
c=0
#echo "${faclis3[@]}";
# loop through sub-array
for f3 in ${faclis3[@]};
do
if [ ${f3} ] && \
[ "${f1}" != "${f3}" ] && \
[ "${f2}" != "${f3}" ];

then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis4=( ${faclis3[@]//${f3}} );
d=0
#echo "${faclis4[@]}";
# loop through sub-array
for f4 in ${faclis4[@]};
do
if [ ${f4} ] && \
[ "${f1}" != "${f4}" ] && \
[ "${f2}" != "${f4}" ] && \
[ "${f3}" != "${f4}" ];
then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3} \
AND ${f4}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1 and \
${f4} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis5=( ${faclis4[@]//${f4}} );
e=0
#echo "${faclis5[@]}";
# loop through sub-array
for f5 in ${faclis5[@]};
do
if [ ${f5} ] && \
[ "${f1}" != "${f5}" ] && \
[ "${f2}" != "${f5}" ] && \
[ "${f3}" != "${f5}" ] && \
[ "${f4}" != "${f5}" ];
then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3} \
AND ${f4} \
AND ${f5}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1 and \
${f4} = 1 and \
${f5} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis6=( ${faclis5[@]//${f5}} );
f=0
#echo "${faclis6[@]}";
# loop through sub-array
for f6 in ${faclis6[@]};
do
if [ ${f6} ] && \
[ "${f1}" != "${f6}" ] && \
[ "${f2}" != "${f6}" ] && \
[ "${f3}" != "${f6}" ] && \
[ "${f4}" != "${f6}" ] && \
[ "${f5}" != "${f6}" ];
then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3} \
AND ${f4} \
AND ${f5} \
AND ${f6}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1 and \
${f4} = 1 and \
${f5} = 1 and \
${f6} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis7=( ${faclis6[@]//${f6}} );
g=0
#echo "${faclis7[@]}";
# loop through sub-array
for f7 in ${faclis7[@]};
do
if [ ${f7} ] && \
[ "${f1}" != "${f7}" ] && \
[ "${f2}" != "${f7}" ] && \
[ "${f3}" != "${f7}" ] && \
[ "${f4}" != "${f7}" ] && \
[ "${f5}" != "${f7}" ] && \
[ "${f6}" != "${f7}" ];
then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3} \
AND ${f4} \
AND ${f5} \
AND ${f6} \
AND ${f7}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1 and \
${f4} = 1 and \
${f5} = 1 and \
${f6} = 1 and \
${f7} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis8=( ${faclis7[@]//${f7}} );
h=0
#echo "${faclis8[@]}";
# loop through sub-array
for f8 in ${faclis8[@]};
do
if [ ${f8} ] && \
[ "${f1}" != "${f8}" ] && \
[ "${f2}" != "${f8}" ] && \
[ "${f3}" != "${f8}" ] && \
[ "${f4}" != "${f8}" ] && \
[ "${f5}" != "${f8}" ] && \
[ "${f6}" != "${f8}" ] && \
[ "${f7}" != "${f8}" ];
then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3} \
AND ${f4} \
AND ${f5} \
AND ${f6} \
AND ${f7} \
AND ${f8}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1 and \
${f4} = 1 and \
${f5} = 1 and \
${f6} = 1 and \
${f7} = 1 and \
${f8} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis9=( ${faclis8[@]//${f8}} );
i=0
#echo "${faclis9[@]}";
# loop through sub-array
for f9 in ${faclis9[@]};
do
if [ ${f9} ] && \
[ "${f1}" != "${f9}" ] && \
[ "${f2}" != "${f9}" ] && \
[ "${f3}" != "${f9}" ] && \
[ "${f4}" != "${f9}" ] && \
[ "${f5}" != "${f9}" ] && \
[ "${f6}" != "${f9}" ] && \
[ "${f7}" != "${f9}" ] && \
[ "${f8}" != "${f9}" ];
then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3} \
AND ${f4} \
AND ${f5} \
AND ${f6} \
AND ${f7} \
AND ${f8} \
AND ${f9}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1 and \
${f4} = 1 and \
${f5} = 1 and \
${f6} = 1 and \
${f7} = 1 and \
${f8} = 1 and \
${f9} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis10=( ${faclis9[@]//${f9}} );
j=0
#echo "${faclis10[@]}";
# loop through sub-array
for f10 in ${faclis10[@]};
do
if [ ${f10} ] && \
[ "${f1}" != "${f10}" ] && \
[ "${f2}" != "${f10}" ] && \
[ "${f3}" != "${f10}" ] && \
[ "${f4}" != "${f10}" ] && \
[ "${f5}" != "${f10}" ] && \
[ "${f6}" != "${f10}" ] && \
[ "${f7}" != "${f10}" ] && \
[ "${f8}" != "${f10}" ] && \
[ "${f9}" != "${f10}" ];
then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3} \
AND ${f4} \
AND ${f5} \
AND ${f6} \
AND ${f7} \
AND ${f8} \
AND ${f9} \
AND ${f10}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1 and \
${f4} = 1 and \
${f5} = 1 and \
${f6} = 1 and \
${f7} = 1 and \
${f8} = 1 and \
${f9} = 1 and \
${f10} = 1;" metamorelia >> permcounts.txt;

# next sub-array
faclis11=( ${faclis10[@]//${f10}} );
k=0
#echo "${faclis11[@]}";
# loop through sub-array
for f11 in ${faclis11[@]};
do
if [ ${f11} ] && \
[ "${f1}" != "${f11}" ] && \
[ "${f2}" != "${f11}" ] && \
[ "${f3}" != "${f11}" ] && \
[ "${f4}" != "${f11}" ] && \
[ "${f5}" != "${f11}" ] && \
[ "${f6}" != "${f11}" ] && \
[ "${f7}" != "${f11}" ] && \
[ "${f8}" != "${f11}" ] && \
[ "${f9}" != "${f11}" ] && \
[ "${f10}" != "${f11}" ];
then
echo "FACTOR ${f1} \
AND ${f2} \
AND ${f3} \
AND ${f4} \
AND ${f5} \
AND ${f6} \
AND ${f7} \
AND ${f8} \
AND ${f9} \
AND ${f10} \
AND ${f11}" >> permcounts.txt;
mysql -u harvey -pdavid -e "select count(clave) from genfact where \
${f1} = 1 and \
${f2} = 1 and \
${f3} = 1 and \
${f4} = 1 and \
${f5} = 1 and \
${f6} = 1 and \
${f7} = 1 and \
${f8} = 1 and \
${f9} = 1 and \
${f10} = 1 and \
${f11} = 1;" metamorelia >> permcounts.txt;

unset faclis11[k];
k=$((${k} + 1));
fi;
done;
unset faclis10[j];
j=$((${j} + 1));
fi;
done;
unset faclis9[i];
i=$((${i} + 1));
fi;
done;
unset faclis8[h];
h=$((${h} + 1));
fi;
done;
unset faclis7[g];
g=$((${g} + 1));
fi;
done;
unset faclis6[f];
f=$((${f} + 1));
fi;
done;
unset faclis5[e];
e=$((${e} + 1));
fi;
done;
unset faclis4[d];
d=$((${d} + 1));
fi;
done;
unset faclis3[c];
c=$((${c} + 1));
fi;
done;
# Remove analyzed factors from vector
unset faclis2[b];
b=$((${b} + 1));
fi;
done;
# remove nth item from array (progressively remove one item)
unset faclis1[a];
# increment n for next round
a=$((${a} + 1));
echo ${n};
fi;
done;

这个脚本有点低效，因为我认为我包含了很多不必要的操作，但它完成了任务。（我想是的。我的学生必须浏览输出文件以确保所有内容都在那里。）

那么您想识别所有2^11组合并计算每个组合的数量吗？这是2048种不同的组合。这就是为什么我希望简化这个过程。其思想是确定文献中出现频率最高的驱动程序组合。使用少量UDF（或连接二进制数字）将驱动程序组合成一个条件字符串。然后使用数据透视表计算每个组合字符串的数量。那么您想识别所有2^11个组合并计算每个组合的数量吗？这是2048种不同的组合。这就是为什么我希望简化这个过程。其思想是确定文献中出现频率最高的驱动程序组合。使用少量UDF（或连接二进制数字）将驱动程序组合成一个条件字符串。然后使用数据透视表计算每个组合字符串的数量。