Mysql 从3个select查询中获取一行结果数据

我有桌子：

玩家：

id
name

地点：

id
playerId
tournamentId

比赛：

id
name
prize1
prize2
prize3

查询：

(
    select pl.Name, pla.place,sum(t2.prize1),count(t2.name) 
    from players pl 
    inner join places pla on pl.id = pla.PlayerId
    inner join tournaments2 t2 on pla.tournamentId = t2.id 
    where pla.place = 1 
    group by pl.name
) union (
    select pl.Name, pla.place,sum(t2.prize2),count(t2.name) 
    from players pl 
    inner join places pla on pl.id = pla.PlayerId
    inner join tournaments2 t2 on pla.tournamentId = t2.id 
    where pla.place = 2 group by pl.name
) union (
    select pl.Name, pla.place,sum(t2.prize3),count(t2.name) 
    from players pl 
    inner join places pla on pl.id = pla.PlayerId
    inner join tournaments2 t2 on pla.tournamentId = t2.id 
    where pla.place = 3 group by pl.name
)

结果:

 Name       place  gold     placecount
"player1"   "1"   "1500"    "2"
"player2"   "1"   "500"     "1"
"player1"   "2"   "300"     "1"
"player1"   "3"   "200"     "1"

所需数据表示：

 name     gold1stplace 1stplacecount gold2ndplace 2ndplacecount gold3rdplace 3rdplacecount
"player1"    "1500"             "3"         "300"         "1"         "200" "1"

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如何实现所需的数据表示？

应该可以使用条件聚合来解决此问题：

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应该可以使用条件聚合来解决此问题：

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问题是什么？我不明白如何从我现在拥有的东西中实现所需的数据表示。问题是什么？我不明白如何从我现在拥有的东西中实现所需的数据表示

SELECT
    p.name player,
    SUM(CASE WHEN pc.place = 1 THEN t.prize1 ELSE 0 END) gold1stplace,
    SUM(CASE WHEN pc.place = 1 THEN 1        ELSE 0 END) place1stcount,
    SUM(CASE WHEN pc.place = 2 THEN t.prize2 ELSE 0 END) gold2ndplace,
    SUM(CASE WHEN pc.place = 2 THEN 1        ELSE 0 END) place2ndcount,
    SUM(CASE WHEN pc.place = 3 THEN t.prize3 ELSE 0 END) gold3rdplace,
    SUM(CASE WHEN pc.place = 3 THEN 1        ELSE 0 END) place3rdcount
FROM 
    players p
    INNER JOIN places pc ON pc.playerId = p.id
    INNER JOIN tournaments t ON t.id = pc.tournamentId
GROUP BY p.name