Mysql 如何将一列中的所有行求和到两个联接表中？

这就是我的问题

这是我的桌子

SELECT movies.name, 
       general.[date], 
       Sum(general.price) AS GeneralPrice
FROM movies 
     INNER JOIN general ON movies.IDmovie=general.IDmovie
GROUP BY movie.name, general.[date]
HAVING SUM(((general.[date])=#8/11/2014#));

因此，通过我的查询，我得到了电影的名称和所有日期为8.11.14的电影的价格，并将它们放在第三个表中。我的问题是如何计算所有价格，比如：

TABLE 1 - MOVIES:

IDmovie | Name 
--------+------------
1       | Something1
2       | Something2
3       | Something3
4       | Something4


TABLE 2 - GENERAL

IDmovie | Date     | Price 
--------+----------+---------
1       | 11.08.14 | $10 
2       | 14.08.14 | $12 
3       | 12.08.14 | $18,60 
4       | 11.08.14 | $20 
5       | 19.08.14 | $13 

---

我应该在查询中添加什么？

这与SQL server有关吗？您不能对日期进行求和。您不想使用常规[date]=#8/11/2014#吗？我对access执行sql查询我不想对日期求和我想对价格求和，但在access的sql视图中

| Date     | Price  | General Price 
+----------+--------+--------------
| 11.08.14 | $10    | $40,60 
| 11.08.14 | $12    |
| 11.08.14 | $18,60 |

DECLARE @movies TABLE
  (
     IDmovie INT,
     Name    VARCHAR(50)
  )

INSERT INTO @movies
VALUES      (1,
             'Something1'),
            (2,
             'Something2'),
            (3,
             'Something3'),
            (4,
             'Something4')

DECLARE @GENERAL TABLE
  (
     IDmovie INT,
     [Date]  DATE,
     Price   FLOAT
  )

INSERT INTO @GENERAL
VALUES      (1,
             '11/aug/14',
             10),
            (2,
             '14/aug/14',
             12),
            (3,
             '11/aug/14',
             18.60),
            (4,
             '11/aug/14',
             20),
            (5,
             '19/aug/14',
             13)

SELECT *
FROM   @movies

SELECT *
FROM   @GENERAL

SELECT g.[date],
       g.Price,
       (SELECT sum(g1.Price)
        FROM   @GENERAL g1
        WHERE  g1.Date = g.Date) AS general_price
FROM   @movies m
       INNER JOIN @GENERAL g
               ON m.IDmovie = g.IDmovie
GROUP  BY g.[date],
          g.Price
HAVING g.[date] = '8/11/2014'