从右表mysql使用空行左连接

我有餐厅和订单表，在订单表中我有

餐厅id

，

状态

和

日期

字段-每天我在订单表中保存一行。如果某一天没有订单，则表示订单表中没有该天的行

我想根据这两个单独的条件在日历上显示每个餐厅当月的数据

1) in first case show only those restaurants that have at least one free 
day during this month(which means for this month at least one date is missing in orders table).

2) in second case show only those restaurants that are free for today 
(which means there is no row for today in orders table)

对于这两种情况，如果条件满足，我应该获取当月的所有订单-这是棘手的部分

通常使用left或internal连接的反连接不能提供所需的结果

谢谢

编辑

输出应该是这样的

(一)

---

2）

这是本月所有今天免费的餐厅的所有列表：

SELECT  r.`id`, r.`name`, o.`date`, o.`status`,  o.`id` order_id
FROM    restaurants r
        INNER JOIN orders o 
            ON r.id = o.restaurant_id
        LEFT JOIN
        (   SELECT  DISTINCT o2.Restaurant_ID
            FROM    orders o2
            WHERE   o2.date = DATE(CURRENT_TIMESTAMP)
        ) o2
            ON r.id = o2.restaurant_id
WHERE   o.Date >= DATE_FORMAT(CURRENT_TIMESTAMP ,'%Y-%m-01')
AND     o.Date <= DATE_FORMAT(DATE_ADD(CURRENT_TIMESTAMP, INTERVAL 1 MONTH) ,'%Y-%m-01')
AND     o2.Restaurant_ID IS NULL;

---

---

这是本月至少有一天空闲时间的所有餐厅本月的所有列表：

SELECT  r.`id`, r.`name`, o.`date`, o.`status`,  o.`id` order_id
FROM    restaurants r
        INNER JOIN orders o 
            ON r.id = o.restaurant_id
            AND o.date BETWEEN '2013-08-10' AND '2013-08-31' 
        INNER JOIN
        (   SELECT  o2.Restaurant_ID
            FROM    orders o2
            WHERE   o2.Date >= DATE_FORMAT(CURRENT_TIMESTAMP ,'%Y-%m-01')
            AND     o2.Date <= DATE_FORMAT(DATE_ADD(CURRENT_TIMESTAMP, INTERVAL 1 MONTH) ,'%Y-%m-01')
            GROUP BY o2.Restaurant_ID
            HAVING COUNT(DISTINCT o2.Date) < DAY(DATE_ADD(DATE_FORMAT(DATE_ADD(CURRENT_TIMESTAMP, INTERVAL 1 MONTH) ,'%Y-%m-01'), INTERVAL -1 DAY))
        ) o2
            ON r.id = o2.restaurant_id
WHERE   o.Date >= DATE_FORMAT(CURRENT_TIMESTAMP ,'%Y-%m-01')
AND     o.Date <= DATE_FORMAT(DATE_ADD(CURRENT_TIMESTAMP, INTERVAL 1 MONTH) ,'%Y-%m-01');

DAY(DATE_ADD(DATE_FORMAT(DATE_ADD(CURRENT_TIMESTAMP, INTERVAL 1 MONTH) ,'%Y-%m-01'), INTERVAL -1 DAY))

然后将结果限制在预订量少于此值的餐厅id：

HAVING COUNT(DISTINCT o2.Date) < DAY(DATE_ADD(DATE_FORMAT(DATE_ADD(CURRENT_TIMESTAMP, INTERVAL 1 MONTH) ,'%Y-%m-01'), INTERVAL -1 DAY))

具有计数（不同的o2.Date）

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@PraveenPrasannan，这些图片能让我了解我想要实现的目标吗？谢谢你，非常感谢你的时间和帮助！！我真的很感激。谢谢

HAVING COUNT(DISTINCT o2.Date) < DAY(DATE_ADD(DATE_FORMAT(DATE_ADD(CURRENT_TIMESTAMP, INTERVAL 1 MONTH) ,'%Y-%m-01'), INTERVAL -1 DAY))