如何在mysql中显示数据,如excel中的pivot

如何在mysql中显示数据,如excel中的pivot,mysql,sql,pivot,Mysql,Sql,Pivot,我有这样的疑问: SELECT DATE,REGION,COUNT(*) FROM ALL_ID_DATA WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8)) AND DIRECTION='inbound' AND REASON_1 = 'complaint' GROUP BY REGION,DATE DESC 结果是 下面的捕获显示的正确查询是什么 有人能帮我吗?我想你在找这个: 这种

我有这样的疑问:

SELECT DATE,REGION,COUNT(*)
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
AND DIRECTION='inbound'
AND REASON_1 = 'complaint'
GROUP BY REGION,DATE DESC
结果是 下面的捕获显示的正确查询是什么


有人能帮我吗?

我想你在找这个:

这种类型的查询称为
透视查询。不幸的是,MySQL没有
PIVOT
函数,因此需要使用
CASE
语句和聚合函数来复制该函数

如果知道要转换的列数,则可以对值进行硬编码:

select region,
  SUM(CASE WHEN date = '2012-09-24' THEN 1 END) as `2012-09-24`,
  SUM(CASE WHEN date = '2012-09-30' THEN 1 END) as `2012-09-30`,
  SUM(CASE WHEN date = '2012-10-01' THEN 1 END) as `2012-10-01`
from ALL_ID_DATA
group by region;

select region,
  COUNT(CASE WHEN date = '2012-09-24' THEN 1 ELSE null END) as `2012-09-24`,
  COUNT(CASE WHEN date = '2012-09-30' THEN 1 ELSE null END) as `2012-09-30`,
  COUNT(CASE WHEN date = '2012-10-01' THEN 1 ELSE null END) as `2012-10-01`
from ALL_ID_DATA
group by region;

然后将其添加到现有查询中,将是:

SELECT REGION,
  SUM(CASE WHEN date = '2012-09-24' THEN 1 END) as `2012-09-24`,
  SUM(CASE WHEN date = '2012-09-30' THEN 1 END) as `2012-09-30`,
  SUM(CASE WHEN date = '2012-10-01' THEN 1 END) as `2012-10-01`
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
  AND DIRECTION='inbound'
  AND REASON_1 = 'complaint'
GROUP BY REGION
SET @sql = NULL;
SELECT
  GROUP_CONCAT(DISTINCT
    CONCAT(
      'sum(case when date = ''',
      date,
      ''' then 1 else 0 end) AS ''',
      Date(date), ''''
    )
  ) INTO @sql
FROM ALL_ID_DATA;

select @sql;

SET @sql = CONCAT('SELECT region, ', @sql, ' 
                   FROM ALL_ID_DATA
                   WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
                   AND DIRECTION=''inbound''
                   AND REASON_1 = ''complaint''');

PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

现在,如果要将未知数量的日期转换为列,则可以使用,并且您的查询类似于此(请参阅):

然后将原始查询放在准备好的语句中,最终查询将是:

SELECT REGION,
  SUM(CASE WHEN date = '2012-09-24' THEN 1 END) as `2012-09-24`,
  SUM(CASE WHEN date = '2012-09-30' THEN 1 END) as `2012-09-30`,
  SUM(CASE WHEN date = '2012-10-01' THEN 1 END) as `2012-10-01`
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
  AND DIRECTION='inbound'
  AND REASON_1 = 'complaint'
GROUP BY REGION
SET @sql = NULL;
SELECT
  GROUP_CONCAT(DISTINCT
    CONCAT(
      'sum(case when date = ''',
      date,
      ''' then 1 else 0 end) AS ''',
      Date(date), ''''
    )
  ) INTO @sql
FROM ALL_ID_DATA;

select @sql;

SET @sql = CONCAT('SELECT region, ', @sql, ' 
                   FROM ALL_ID_DATA
                   WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
                   AND DIRECTION=''inbound''
                   AND REASON_1 = ''complaint''');

PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;