MySQL：按多列排序结果

假设我有下表“产品”：

+----+------------+------------+----------+------+
| ID | Name       | Purchased  | Promoted | Used |
+----+------------+------------+----------+------+
| 0  | TV         | 2017-10-02 | 0        | 0    |
| 1  | Radio      | 2017-08-27 | 1        | 0    |
| 2  | Fridge     | 2017-09-03 | 1        | 1    |
| 3  | Dishwasher | 2017-08-15 | 0        | 1    |
| 4  | Bike       | 2017-09-17 | 0        | 1    |
| 5  | Computer   | 2017-10-03 | 0        | 0    |
+----+------------+------------+----------+------+

现在，我想按以下顺序获取所有记录：

按“已购买”列排序的“已升级=1”行

按“已购买”列排序的“已使用=1”行

按“已购买”列排序的剩余行

结果:

+---+------------+------------+---+---+
| 2 | Fridge     | 2017-09-03 | 1 | 1 |
+---+------------+------------+---+---+
| 1 | Radio      | 2017-08-27 | 1 | 0 |
| 4 | Bike       | 2017-09-17 | 0 | 1 |
| 3 | Dishwasher | 2017-08-15 | 0 | 1 |
| 5 | Computer   | 2017-10-03 | 0 | 0 |
| 0 | TV         | 2017-10-02 | 0 | 0 |
+---+------------+------------+---+---+

---

MySQL查询是什么？

看起来很简单：

ORDER BY Promoted = 1 DESC,
         Used = 1 DESC,
         Purchased DESC

---

MySQL将布尔表达式计算为1和0。

您可以使用UNION语句，如

SELECT * FROM products WHERE Promoted='1' ORDER BY Purchased 
UNION 
SELECT * FROM products WHERE Promoted!='1' AND Used='1' ORDER BY Purchased
UNION 
SELECT * FROM products WHERE Promoted!='1' AND Used!='1' ORDER BY Purchased

---

从产品订单中按PRODUCT.PROMOTED DESC、PRODUCT.USED DESC选择*

我看不到你的尝试？！！？