MySQL+；JSON：检索id=term的所有数据_Mysql_Json_Html Table

MySQL+；JSON：检索id=term的所有数据

mysql json

MySQL+；JSON：检索id=term的所有数据,mysql,json,html-table,Mysql,Json,Html Table,我试图从数据库中检索JSON数据，并在表中解析它们目前我检索它的方式如下： xmlhttp = new XMLHttpRequest() xmlhttp.onreadystatechange = function () { if (xmlhttp.readyState == 4 && xmlhttp.status == 200) { var jsontext = xmlhttp.responseText; var json = JSON

我试图从数据库中检索JSON数据，并在表中解析它们

目前我检索它的方式如下：

xmlhttp = new XMLHttpRequest()

xmlhttp.onreadystatechange = function () {
    if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
        var jsontext = xmlhttp.responseText;
        var json = JSON.parse(jsontext);

        console.log(json.service)

    }
}

xmlhttp.open("GET", "mysql.php?p=getservice" + "&carid=" + "KYF111", true);
xmlhttp.send();

case 'getservice':

$q = mysql_real_escape_string($_GET['q']);
$carid = stripslashes($_GET['carid']);
$query = "SELECT * FROM Service WHERE carid = '".$carid."'";

$result = mysql_query($query);

$json = array();
while ($row = mysql_fetch_array($result)) {

    $json['carid'] = $row['carid'];
    $json['service'] = $row['service'];
    $json['date'] = $row['date'];
    $json['nextdate'] = $row['nextdate'];
    $json['kilometers'] = $row['kilometers'];
    $json['servicedby'] = $row['servicedby'];
    $json['invoice'] = $row['invoice'];
    $json['cost'] = $row['cost'];
    $json['remarks'] = $row['remarks'];

}
print json_encode($json);

mysql_close();

break;

<tbody>
    <tr>
        <td>Tyre</td>
        <td>10-10-2012</td>
        <td>31-10-2012</td>
        <td></td>
        <td>George</td>
        <td>8951235</td>
        <td>0</td>
        <td>Lorem Ipsum</td>
    </tr>
    <tr>
        <td>Lights</td>
        <td>17-10-2012</td>
        <td>23-10-2012</td>
        <td></td>
        <td>Antony</td>
        <td>4367234</td>
        <td>0</td>
        <td>Lorem Ipsum</td>
    </tr>
</tbody>

    $temp=0;
    $json = array();
        while ($row = mysql_fetch_array($result)) {

            $json[$temp]['carid'] = $row['carid'];
            $json[$temp]['service'] = $row['service'];
            $json[$temp]['date'] = $row['date'];
            $json[$temp]['nextdate'] = $row['nextdate'];
            $json[$temp]['kilometers'] = $row['kilometers'];
            $json[$temp]['servicedby'] = $row['servicedby'];
            $json[$temp]['invoice'] = $row['invoice'];
            $json[$temp]['cost'] = $row['cost'];
            $json[$temp]['remarks'] = $row['remarks'];
    $temp++;
        }
print json_encode($json);

这将给我一个结果，不管有多少行id为“term”

我的mysql.php文件如下所示：

xmlhttp = new XMLHttpRequest()

xmlhttp.onreadystatechange = function () {
    if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
        var jsontext = xmlhttp.responseText;
        var json = JSON.parse(jsontext);

        console.log(json.service)

    }
}

xmlhttp.open("GET", "mysql.php?p=getservice" + "&carid=" + "KYF111", true);
xmlhttp.send();

case 'getservice':

$q = mysql_real_escape_string($_GET['q']);
$carid = stripslashes($_GET['carid']);
$query = "SELECT * FROM Service WHERE carid = '".$carid."'";

$result = mysql_query($query);

$json = array();
while ($row = mysql_fetch_array($result)) {

    $json['carid'] = $row['carid'];
    $json['service'] = $row['service'];
    $json['date'] = $row['date'];
    $json['nextdate'] = $row['nextdate'];
    $json['kilometers'] = $row['kilometers'];
    $json['servicedby'] = $row['servicedby'];
    $json['invoice'] = $row['invoice'];
    $json['cost'] = $row['cost'];
    $json['remarks'] = $row['remarks'];

}
print json_encode($json);

mysql_close();

break;

<tbody>
    <tr>
        <td>Tyre</td>
        <td>10-10-2012</td>
        <td>31-10-2012</td>
        <td></td>
        <td>George</td>
        <td>8951235</td>
        <td>0</td>
        <td>Lorem Ipsum</td>
    </tr>
    <tr>
        <td>Lights</td>
        <td>17-10-2012</td>
        <td>23-10-2012</td>
        <td></td>
        <td>Antony</td>
        <td>4367234</td>
        <td>0</td>
        <td>Lorem Ipsum</td>
    </tr>
</tbody>

    $temp=0;
    $json = array();
        while ($row = mysql_fetch_array($result)) {

            $json[$temp]['carid'] = $row['carid'];
            $json[$temp]['service'] = $row['service'];
            $json[$temp]['date'] = $row['date'];
            $json[$temp]['nextdate'] = $row['nextdate'];
            $json[$temp]['kilometers'] = $row['kilometers'];
            $json[$temp]['servicedby'] = $row['servicedby'];
            $json[$temp]['invoice'] = $row['invoice'];
            $json[$temp]['cost'] = $row['cost'];
            $json[$temp]['remarks'] = $row['remarks'];
    $temp++;
        }
print json_encode($json);

以下是我的数据库的外观：

因此这个术语将是carid，我想要包含carid这个术语的行中的所有值。然后，单行上的每个值都在一个值之间。大概是这样的：

xmlhttp = new XMLHttpRequest()

xmlhttp.onreadystatechange = function () {
    if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
        var jsontext = xmlhttp.responseText;
        var json = JSON.parse(jsontext);

        console.log(json.service)

    }
}

xmlhttp.open("GET", "mysql.php?p=getservice" + "&carid=" + "KYF111", true);
xmlhttp.send();

case 'getservice':

$q = mysql_real_escape_string($_GET['q']);
$carid = stripslashes($_GET['carid']);
$query = "SELECT * FROM Service WHERE carid = '".$carid."'";

$result = mysql_query($query);

$json = array();
while ($row = mysql_fetch_array($result)) {

    $json['carid'] = $row['carid'];
    $json['service'] = $row['service'];
    $json['date'] = $row['date'];
    $json['nextdate'] = $row['nextdate'];
    $json['kilometers'] = $row['kilometers'];
    $json['servicedby'] = $row['servicedby'];
    $json['invoice'] = $row['invoice'];
    $json['cost'] = $row['cost'];
    $json['remarks'] = $row['remarks'];

}
print json_encode($json);

mysql_close();

break;

<tbody>
    <tr>
        <td>Tyre</td>
        <td>10-10-2012</td>
        <td>31-10-2012</td>
        <td></td>
        <td>George</td>
        <td>8951235</td>
        <td>0</td>
        <td>Lorem Ipsum</td>
    </tr>
    <tr>
        <td>Lights</td>
        <td>17-10-2012</td>
        <td>23-10-2012</td>
        <td></td>
        <td>Antony</td>
        <td>4367234</td>
        <td>0</td>
        <td>Lorem Ipsum</td>
    </tr>
</tbody>

    $temp=0;
    $json = array();
        while ($row = mysql_fetch_array($result)) {

            $json[$temp]['carid'] = $row['carid'];
            $json[$temp]['service'] = $row['service'];
            $json[$temp]['date'] = $row['date'];
            $json[$temp]['nextdate'] = $row['nextdate'];
            $json[$temp]['kilometers'] = $row['kilometers'];
            $json[$temp]['servicedby'] = $row['servicedby'];
            $json[$temp]['invoice'] = $row['invoice'];
            $json[$temp]['cost'] = $row['cost'];
            $json[$temp]['remarks'] = $row['remarks'];
    $temp++;
        }
print json_encode($json);


轮胎
10-10-2012
31-10-2012
乔治
8951235
0
乱数假文
灯
17-10-2012
23-10-2012
安东尼
4367234
0
乱数假文

您的

while

循环每次都覆盖相同的数组项，而不是生成二维数组。应该是：

$json = array();
while ($row = mysql_fetch_array($result)) {
  $json[] = $row;
}
echo json_encode($json);

for (var i = 0; i < json.length; i++) {
    console.log(json[i].service);
}

在JavaScript中，需要循环返回的数组。而不是

console.log（json.service）

它应该是：

$json = array();
while ($row = mysql_fetch_array($result)) {
  $json[] = $row;
}
echo json_encode($json);

for (var i = 0; i < json.length; i++) {
    console.log(json[i].service);
}

for（var i=0；i

试着这样做：
xmlhttp = new XMLHttpRequest()

xmlhttp.onreadystatechange = function () {
    if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
        var jsontext = xmlhttp.responseText;
        var json = JSON.parse(jsontext);

        console.log(json.service)

    }
}

xmlhttp.open("GET", "mysql.php?p=getservice" + "&carid=" + "KYF111", true);
xmlhttp.send();

case 'getservice':

$q = mysql_real_escape_string($_GET['q']);
$carid = stripslashes($_GET['carid']);
$query = "SELECT * FROM Service WHERE carid = '".$carid."'";

$result = mysql_query($query);

$json = array();
while ($row = mysql_fetch_array($result)) {

    $json['carid'] = $row['carid'];
    $json['service'] = $row['service'];
    $json['date'] = $row['date'];
    $json['nextdate'] = $row['nextdate'];
    $json['kilometers'] = $row['kilometers'];
    $json['servicedby'] = $row['servicedby'];
    $json['invoice'] = $row['invoice'];
    $json['cost'] = $row['cost'];
    $json['remarks'] = $row['remarks'];

}
print json_encode($json);

mysql_close();

break;

<tbody>
    <tr>
        <td>Tyre</td>
        <td>10-10-2012</td>
        <td>31-10-2012</td>
        <td></td>
        <td>George</td>
        <td>8951235</td>
        <td>0</td>
        <td>Lorem Ipsum</td>
    </tr>
    <tr>
        <td>Lights</td>
        <td>17-10-2012</td>
        <td>23-10-2012</td>
        <td></td>
        <td>Antony</td>
        <td>4367234</td>
        <td>0</td>
        <td>Lorem Ipsum</td>
    </tr>
</tbody>

    $temp=0;
    $json = array();
        while ($row = mysql_fetch_array($result)) {

            $json[$temp]['carid'] = $row['carid'];
            $json[$temp]['service'] = $row['service'];
            $json[$temp]['date'] = $row['date'];
            $json[$temp]['nextdate'] = $row['nextdate'];
            $json[$temp]['kilometers'] = $row['kilometers'];
            $json[$temp]['servicedby'] = $row['servicedby'];
            $json[$temp]['invoice'] = $row['invoice'];
            $json[$temp]['cost'] = $row['cost'];
            $json[$temp]['remarks'] = $row['remarks'];
    $temp++;
        }
print json_encode($json);

我仍然只得到一个值，即lights。您的JavaScript必须在数组上循环，请参阅我编辑的答案。我很惊讶你在控制台上记录了任何东西。在这种情况下，两者都可以工作。有关差异的解释，请参阅。我没有得到任何结果。我不确定我做错了什么。检索数据的方法正确吗？您在该PHP页面上设置了JSON头了吗？