Mysql 错误代码：1242。子查询返回超过1行（对于所有记录）

这里我需要通过AgentID获取所有记录组，但它显示错误：错误代码：1242。子查询返回超过1行

表:

 customerID  amountreceived date_time area agentID paymentmode
   1            2000         5/13/2014 hyd   1       cash


enter code here

 DELIMITER $$
 CREATE DEFINER=`ntc`@`%` PROCEDURE `spforallAgents`()
 BEGIN
select 
(select 
        @DayAmount:=sum(AmountRecevied) as Totoalamountperday
    from
        collection_master
    where  day(Date_Time) = day(CURRENT_DATE())   group by AgentID),
(select 
        @MonthAmount:=sum(AmountRecevied) as Totoalamountperday
    from
        collection_master
    where  date_time between DATE_FORMAT(NOW(), '%Y-%m-01') and LAST_DAY(now() - interval 0 month) group by AgentID),
    (select 
        @YearAmount:=sum(AmountRecevied) as Totoalamountpermonth
    from
        collection_master where  year(Date_Time) = YEAR(CURRENT_DATE()) group by AgentID),
 (select 
        @Position:=@Position + 1 AS Rank
    from
        collection_master,
        (SELECT @Position:=0) r group by AgentID) as position;

END

---

使用连接，您可以执行以下未经测试的操作：-

SELECT AgentID, 
        current_date_amount, 
        date_range_amount, 
        month_amount,
        @Position:=@Position + 1 AS `Rank`
FROM
(
    SELECT just_agent.AgentID, 
            total_current_date.Totoalamountperday AS current_date_amount, 
            total_date_range.Totoalamountperday AS date_range_amount, 
            total_month.Totoalamountpermonth AS month_amount
    FROM
    (
        SELECT DISTINCT AgentID
        FROM collection_master
    ) just_agent
    LEFT OUTER JOIN
    (
        select AgentID, SUM(AmountRecevied) as Totoalamountperday
        from collection_master
        where  day(Date_Time) = day(CURRENT_DATE())
        group by AgentID
    ) total_current_date
    ON just_agent.AgentID = total_current_date.AgentID
    LEFT OUTER JOIN
    (
        select AgentID, sum(AmountRecevied) as Totoalamountperday
        from collection_master
        where  date_time between DATE_FORMAT(NOW(), '%Y-%m-01') and LAST_DAY(now() - interval 0 month) 
        group by AgentID
    ) total_date_range
    ON just_agent.AgentID = total_date_range.AgentID
    LEFT OUTER JOIN
    (
        select AgentID, sum(AmountRecevied) as Totoalamountpermonth
        from collection_master 
        where  year(Date_Time) = YEAR(CURRENT_DATE()) 
        group by AgentID
    ) total_month
    ON just_agent.AgentID = total_month.AgentID
    ORDER BY total_month.Totoalamountpermonth DESC
) Sub1
CROSS JOIN (SELECT @Position:=0) Sub2

请注意，这是在做一些假设。例如，您最初的查询没有明确指定我假设的排名下降到OALAMOUNTPERMONTH的顺序。另外，如果有另一个表提供代理ID，而不是使用额外的子查询来获取不同的AgentID，则会更简单

SQL fiddle for it：-

编辑

使用来自另一个线程的代码加入对自身的查询，M.Massias值得称赞

SELECT t2.*
FROM 
(
    SELECT AgentID, 
            current_date_amount, 
            date_range_amount, 
            month_amount,
            @Position1:=@Position1 + 1 AS `Rank`
    FROM
    (
        SELECT just_agent.AgentID, 
                total_current_date.Totoalamountperday AS current_date_amount, 
                total_date_range.Totoalamountperday AS date_range_amount, 
                total_month.Totoalamountpermonth AS month_amount
        FROM
        (
            SELECT DISTINCT AgentID
            FROM collection_master
        ) just_agent
        LEFT OUTER JOIN
        (
            select AgentID, SUM(AmountRecevied) as Totoalamountperday
            from collection_master
            where  day(Date_Time) = day(CURRENT_DATE())
            group by AgentID
        ) total_current_date
        ON just_agent.AgentID = total_current_date.AgentID
        LEFT OUTER JOIN
        (
            select AgentID, sum(AmountRecevied) as Totoalamountperday
            from collection_master
            where  date_time between DATE_FORMAT(NOW(), '%Y-%m-01') and LAST_DAY(now() - interval 0 month) 
            group by AgentID
        ) total_date_range
        ON just_agent.AgentID = total_date_range.AgentID
        LEFT OUTER JOIN
        (
            select AgentID, sum(AmountRecevied) as Totoalamountpermonth
            from collection_master 
            where  year(Date_Time) = YEAR(CURRENT_DATE()) 
            group by AgentID
        ) total_month
        ON just_agent.AgentID = total_month.AgentID
        ORDER BY total_month.Totoalamountpermonth DESC
    ) Sub1
    CROSS JOIN (SELECT @Position1:=0) Sub2
) t1
JOIN 
(
    SELECT AgentID, 
            current_date_amount, 
            date_range_amount, 
            month_amount,
            @Position2:=@Position2 + 1 AS `Rank`
    FROM
    (
        SELECT just_agent.AgentID, 
                total_current_date.Totoalamountperday AS current_date_amount, 
                total_date_range.Totoalamountperday AS date_range_amount, 
                total_month.Totoalamountpermonth AS month_amount
        FROM
        (
            SELECT DISTINCT AgentID
            FROM collection_master
        ) just_agent
        LEFT OUTER JOIN
        (
            select AgentID, SUM(AmountRecevied) as Totoalamountperday
            from collection_master
            where  day(Date_Time) = day(CURRENT_DATE())
            group by AgentID
        ) total_current_date
        ON just_agent.AgentID = total_current_date.AgentID
        LEFT OUTER JOIN
        (
            select AgentID, sum(AmountRecevied) as Totoalamountperday
            from collection_master
            where  date_time between DATE_FORMAT(NOW(), '%Y-%m-01') and LAST_DAY(now() - interval 0 month) 
            group by AgentID
        ) total_date_range
        ON just_agent.AgentID = total_date_range.AgentID
        LEFT OUTER JOIN
        (
            select AgentID, sum(AmountRecevied) as Totoalamountpermonth
            from collection_master 
            where  year(Date_Time) = YEAR(CURRENT_DATE()) 
            group by AgentID
        ) total_month
        ON just_agent.AgentID = total_month.AgentID
        ORDER BY total_month.Totoalamountpermonth DESC
    ) Sub1
    CROSS JOIN (SELECT @Position2:=0) Sub2
) t2
ON ABS(t1.`Rank` - t2.`Rank`) <= 1.5 
WHERE t1.AgentID = 2

---

您的子查询似乎都没有按AgentID缩小结果范围，而只是按AgentID分组。因此，每个AgentId返回一条记录是的，但根据数据日金额为2条记录，月金额为3条记录，代理id为3条记录，因此如何检查null并将null或0分配给列o/p值？按要求执行。我将在稍后给出一个示例，仅针对单个表您正在使用子查询，但您可以从子查询中执行一个操作，并将它们连接在一起，而不是将它们放在主SELECT子句中。如果您发布带有一些示例数据的表声明，以及您希望该示例数据的结果，我可以玩得更多。错误代码：1054。“字段列表”中的未知列“total\u current\u date.ToToToAlaMountPerDay”尝试该选项。但是请发布表格布局等，所以我有机会测试它。错误代码：1054。“字段列表”中的未知列“just_agent.AgentID”，在SQL FIDLE中对其进行了快速测试。现在尝试上面的版本如果我选择agentID-2 ex他的排名仅为2我如何显示1、2和3条记录？即他的排名前和排名后记录