Mysql Microsoft SQL-返回每个部门的男性、女性和员工总数

我正在努力解决这个问题

本质上，我需要做的是创建一个查询，返回一个统计每个部门所有女性、男性和总员工的表

到目前为止，我已经能够显示所有部门以及女性、男性和员工的总数，但不是每个部门（它显示每个部门的相同数量）

如何仅显示每个部门的男性、女性和员工总数

问题和代码如下。以及代码生成的输出

提前谢谢各位

-- Username:
-- Q1004 For each of the different departments, show the number of current female, male and total
-- employees currently employed.
-- Schemas: HumanResources

-- Example output:
-- departmentName   female  male    totalEmployeeCount
-- Production        40     120         160

-- Write your query below


SELECT Name AS departmentName, 
(SELECT COUNT(gender) FROM AdventureWorksDB.HumanResources.Employee WHERE Gender = 'F') AS female,
(SELECT COUNT(gender) FROM AdventureWorksDB.HumanResources.Employee WHERE Gender = 'M') AS male,
(SELECT COUNT(gender) FROM AdventureWorksDB.HumanResources.Employee) AS totalEmployeeCount

FROM AdventureWorksDB.HumanResources.Department N 
JOIN AdventureWorksDB.HumanResources.EmployeeDepartmentHistory EDH 
ON N.DepartmentID = EDH.DepartmentID
JOIN AdventureWorksDB.HumanResources.Employee E
ON EDH.BusinessEntityID = E.BusinessEntityID
GROUP BY Name

输出结果如下所示

Department                female|male   |totalEmployeeCount
Engineering                84   |206    |290
Tool Design                84   |206    |290
Sales                      84   |206    |290
Marketing                  84   |206    |290
Purchasing                 84   |206    |290
Research and Development   84   |206    |290
Production                 84   |206    |290

---

使用条件聚合：

SELECT Name AS departmentName, 
       SUM(CASE WHEN e.gender = 'F' THEN 1 ELSE 0 END) as famale,
       SUM(CASE WHEN e.gender = 'M' THEN 1 ELSE 0 END) as male,
       COUNT(*) as totalEmployeeCount
FROM AdventureWorksDB.HumanResources.Department N JOIN 
     AdventureWorksDB.HumanResources.EmployeeDepartmentHistory EDH 
     ON N.DepartmentID = EDH.DepartmentID JOIN
     AdventureWorksDB.HumanResources.Employee E
     ON EDH.BusinessEntityID = E.BusinessEntityID
GROUP BY Name