MYSQl-组_Concat中的元素计数

我是MYSQL的新手，在group_concat语句中需要一些帮助。我有下表

Seller Merchant CustomerID
S1     M1       C1
S1     M1       C1
S1     M1       C2
S1     M1       C3
S1     M1       C4
S2     M2       C5
S2     M2       C6
S3     M3       C6

对于同一卖家和商户的组合，具有不同CustomerID的所有项目以及重复次数的计数

我能够使用group_concat获得唯一客户ID的计数，但无法获得计数

SELECT * , LENGTH(CUSTIDS) - LENGTH(REPLACE(CUSTIDS,',',''))+1 AS COUNT_OF_CUSTIDS
FROM (SELECT SELLER, MERCHANT, GROUP_CONCAT(CUSTOMERID SEPARATOR '|') AS CUSTIDS
FROM TABLE
GROUP BY SELLER, MERCHANT
HAVING COUNT(DISTINCT CUSTOMERID ) >1 
)

这给了我下面的结果

Seller Merchant CustomerID    COUNT_OF_CUSTIDS
S1     M1       C1,C2,C3,C4   4
S2     M2       C5,C6         2

而我想要下面的

Seller Merchant CustomerID                 COUNT_OF_CUSTIDS
S1     M1       C1(2),C2(1),C3(1),C4(1)    4
S2     M2       C5(1),C6(1)                2

---

您需要首先在

卖家

/

商户

/

客户ID

级别进行汇总，以获得计数。然后，您可以继续进行聚合：

  SELECT SELLER, MERCHANT,
         COUNT(*) as COUNT_OF_CUSTIDS,
         GROUP_CONCAT(CUSTOMERID, ' (', cnt, ')' SEPARATOR '|') AS CUSTIDS
  FROM (SELECT SELLER, MERCHANT, COUNT(*) as cnt
        FROM TABLE
        GROUP BY SELLER, MERCHANT, CUSTOMERID
       ) t
  GROUP BY SELLER, MERCHANT
  HAVING COUNT(* ) > 1 

---

您需要首先在

卖家

/

商户

/

客户ID

级别进行汇总，以获得计数。然后，您可以继续进行聚合：

  SELECT SELLER, MERCHANT,
         COUNT(*) as COUNT_OF_CUSTIDS,
         GROUP_CONCAT(CUSTOMERID, ' (', cnt, ')' SEPARATOR '|') AS CUSTIDS
  FROM (SELECT SELLER, MERCHANT, COUNT(*) as cnt
        FROM TABLE
        GROUP BY SELLER, MERCHANT, CUSTOMERID
       ) t
  GROUP BY SELLER, MERCHANT
  HAVING COUNT(* ) > 1