Mysql 仅选择“按列分组”，而不选择“聚合”

在涉及聚合的MySql select语句中，是否可以只选择分组按列而不选择聚合

基本上，我希望根据基于聚合的条件在子查询中选择ID，在这种情况下，向客户支付的总金额：

select idclient, business_name from client where idclient in
(
  select idclient, sum(amount) as total 
  from payment 
  group by idclient
  having total > 100
)

。。。但是这失败了，因为操作数应该包含1列，因为子查询同时选择了我想要的id和我不想要的总数。我可以以任何方式从子查询结果中排除total吗

编辑：如果可能的话，我希望避免使用join-where子句被单独传递到另一个现有函数上

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如果这是一个骗局，我道歉-我确实搜索过，诚实。在大量的SQL聚合问题中，我找不到确切的答案。

您的查询应该是这样的：

select idclient, business_name from client where idclient in
(
  select idclient 
  from payment 
  group by idclient
  having sum(amount) > 100
)

SELECT c.idclient, c.business_name
FROM payment p
  INNER JOIN client c ON c.idclient = p.idclient
GROUP BY c.idclient
HAVING SUM(p.amount) > 100

---

您需要在having子句中放置聚合函数，在sub查询中，您需要选择与where子句中相同的列。

您的查询应如下所示：

select idclient, business_name from client where idclient in
(
  select idclient 
  from payment 
  group by idclient
  having sum(amount) > 100
)

WHERE idclient IN (...)

SELECT c.idclient, c.business_name
FROM payment p
  INNER JOIN client c ON c.idclient = p.idclient
GROUP BY c.idclient
HAVING SUM(p.amount) > 100

您需要将聚合函数放在having子句中，并在子查询中选择与where子句中相同的列

WHERE idclient IN (...)

里面的东西。。。是一个子查询。显然，它应该只返回一列，因为IN子句只需要一列数据

您可以通过以下方式忽略“总计”列：

SELECT idclient
FROM payment
GROUP BY idclient
HAVING SUM(amount) > 100

里面的东西。。。是一个子查询。显然，它应该只返回一列，因为IN子句只需要一列数据

您可以通过以下方式忽略“总计”列：

SELECT idclient
FROM payment
GROUP BY idclient
HAVING SUM(amount) > 100

---

你也可以试试这个：

SELECT c.idclient, c.business_name
FROM payment p
  INNER JOIN client c ON c.idclient = p.idclient
GROUP BY c.idclient, c.business_name
HAVING SUM(p.amount) > 100

而且，由于client.idclient列看起来非常像PK，您甚至可以从GROUPBY中省略client.business_名称。因此，最终的查询如下所示：

select idclient, business_name from client where idclient in
(
  select idclient 
  from payment 
  group by idclient
  having sum(amount) > 100
)

SELECT c.idclient, c.business_name
FROM payment p
  INNER JOIN client c ON c.idclient = p.idclient
GROUP BY c.idclient
HAVING SUM(p.amount) > 100

---

你也可以试试这个：

SELECT c.idclient, c.business_name
FROM payment p
  INNER JOIN client c ON c.idclient = p.idclient
GROUP BY c.idclient, c.business_name
HAVING SUM(p.amount) > 100

而且，由于client.idclient列看起来非常像PK，您甚至可以从GROUPBY中省略client.business_名称。因此，最终的查询如下所示：

select idclient, business_name from client where idclient in
(
  select idclient 
  from payment 
  group by idclient
  having sum(amount) > 100
)

SELECT c.idclient, c.business_name
FROM payment p
  INNER JOIN client c ON c.idclient = p.idclient
GROUP BY c.idclient
HAVING SUM(p.amount) > 100

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谢谢我不知道我是从哪里想到“having”只能使用选定的列：\Thank！我不知道我是从哪里想到“having”只能使用选定的列：\