如何在MySQL中实现这个查询？

我的问题与此非常相似

(SELECT emailid FROM usereducation WHERE presfuncarea = '$funcarea') 
intersect
(SELECT emailid FROM userprofession WHERE totexpyear >= '$minexp')

---

由于MySQL不支持intersect，我必须找到正确的解决方案

存在MySQL支持。这应该起作用：

SELECT UE.emailid
FROM usereducation AS UE
WHERE UE.presfuncarea = '$funcarea'
  AND NOT EXISTS
    (
    SELECT * FROM userprofession AS UP
    WHERE UE.emailid = UP.emailID AND UP.totexpyear >= '$minexp'
    )

发件人：

INTERSECT只是一个内部联接，我们将一个表的元组与另一个表的元组进行比较，然后选择出现在这两个表中的元组，同时剔除重复的元组。所以

可以简单地重写为

SELECT a.member_id, a.name
FROM a INNER JOIN b
USING (member_id, name)

---

这应该可以做到：

SELECT p.emailid
FROM usereducation e JOIN userprofession p ON p.emailid = e.emailid
WHERE e.presfuncarea = '$funcarea'
AND p.totexpyear >= '$minexp'

SELECT p.emailid
FROM usereducation e JOIN userprofession p ON p.emailid = e.emailid
WHERE e.presfuncarea = '$funcarea'
AND p.totexpyear >= '$minexp'