Mysql 如何创建一个新表，该表根据名称获取其他表中列的平均值

它给了我错误代码1166。如果我省略了“createtable Professor_average”，那么脚本将运行，但我没有创建表

尝试命名计算列：

CREATE TABLE Average_Professor

SELECT ie.Instructor
      ,SUM(ie.instreffective_avg + h.howmuchlearned_avg + ir.instrrespect_avg +
 iv.instroverall_avg + av.availability_avg)/5
FROM   instreffective_average ie
JOIN   howmuchlearned_average h  USING (Instructor)
JOIN   instrrespect_average   ir USING (Instructor)
JOIN   instructoroverall_average   iv USING (Instructor)
JOIN   availability_average   av USING (Instructor)
GROUP  BY Instructor

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尝试命名计算列：

CREATE TABLE Average_Professor

SELECT ie.Instructor
      ,SUM(ie.instreffective_avg + h.howmuchlearned_avg + ir.instrrespect_avg +
 iv.instroverall_avg + av.availability_avg)/5
FROM   instreffective_average ie
JOIN   howmuchlearned_average h  USING (Instructor)
JOIN   instrrespect_average   ir USING (Instructor)
JOIN   instructoroverall_average   iv USING (Instructor)
JOIN   availability_average   av USING (Instructor)
GROUP  BY Instructor

---

是的，这将创建一个名为calculation\u value的新列，但我希望将所有这些信息创建为一个新表。对不起，我忘记了create table语句。更新了答案。是，这将创建一个名为calculation_value的新列，但我希望将所有这些信息创建为一个新表。抱歉，我忘记了create table语句。更新了答案。