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为什么这些查询在MySQL 5.5和5.6中产生不同的结果?_Mysql - Fatal编程技术网

为什么这些查询在MySQL 5.5和5.6中产生不同的结果?

为什么这些查询在MySQL 5.5和5.6中产生不同的结果?,mysql,Mysql,有人能解释一下为什么这两个查询(一个在中使用,另一个使用存在)在MySQL 5.6中返回不同的结果,而在MySQL 5.5中却没有 通过使用EXPLAIN,我可以看到每个项目的不同执行计划,但我需要帮助了解发生了什么,以及为什么逻辑中的会在5.6而不是5.5中被破坏 Fiddle举例说明问题: 成员可以有两个地址:家庭地址和公司地址。所需的结果是提供一个区域X,并获得该区域中具有邮寄地址的所有成员的列表。邮寄地址是公司地址(如果存在),否则是家庭地址。城市可以属于一个或多个地区 简化的数据库结构

有人能解释一下为什么这两个查询(一个在中使用
,另一个使用
存在
)在MySQL 5.6中返回不同的结果,而在MySQL 5.5中却没有

通过使用
EXPLAIN
,我可以看到每个项目的不同执行计划,但我需要帮助了解发生了什么,以及为什么
逻辑中的
会在5.6而不是5.5中被破坏

Fiddle举例说明问题:

成员可以有两个地址:家庭地址和公司地址。所需的结果是提供一个区域X,并获得该区域中具有邮寄地址的所有成员的列表。邮寄地址是公司地址(如果存在),否则是家庭地址。城市可以属于一个或多个地区

简化的数据库结构和数据:

CREATE TABLE `city` (
  `c_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `c_name` varchar(255) NOT NULL DEFAULT '',
  PRIMARY KEY (`c_id`)
);

INSERT INTO `city`
VALUES
  ('1', 'Hillsdale'),
  ('2', 'Smallville'),
  ('3', 'Oakside'),
  ('4', 'Lakeview');

CREATE TABLE `city_region` (
  `cr_city` int(11) unsigned NOT NULL,
  `cr_region` int(11) NOT NULL,
  PRIMARY KEY (`cr_city`,`cr_region`)
);

INSERT INTO `city_region`
VALUES
  ('1', '3'),
  ('2', '1'),
  ('3', '1'),
  ('3', '2'),
  ('4', '1'),
  ('4', '3');

CREATE TABLE `firm_address` (
  `fa_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `fa_member` int(11) NOT NULL,
  `fa_city` int(11) NOT NULL,
  PRIMARY KEY (`fa_id`)
);

INSERT INTO `firm_address`
VALUES
  ('1', '1', '3'),
  ('2', '2', '2'),
  ('3', '3', '1'),
  ('4', '6', '2'),
  ('5', '7', '1');

CREATE TABLE `home_address` (
  `ha_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `ha_member` int(11) NOT NULL,
  `ha_city` int(11) NOT NULL,
  PRIMARY KEY (`ha_id`)
);

INSERT INTO `home_address`
VALUES
  ('1', '1', '2'),
  ('2', '2', '3'),
  ('3', '3', '1'),
  ('4', '4', '1'),
  ('5', '5', '2'),
  ('6', '6', '2');

CREATE TABLE `member` (
  `m_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `m_name` varchar(255) NOT NULL DEFAULT '',
  PRIMARY KEY (`m_id`)
);

INSERT INTO `member`
VALUES
  ('1', 'John'),
  ('2', 'Bob'),
  ('3', 'Dave'),
  ('4', 'Jane'),
  ('5', 'Mary'),
  ('6', 'Karen'),
  ('7', 'Christie');

CREATE TABLE `region` (
  `r_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `r_name` varchar(255) NOT NULL DEFAULT '',
  PRIMARY KEY (`r_id`)
);

INSERT INTO `region`
VALUES
  ('1', 'Central'),
  ('2', 'Lake District'),
  ('3', 'Westside');
SELECT * FROM member

LEFT OUTER JOIN home_address ON m_id = ha_member
LEFT OUTER JOIN city home_city ON ha_city = home_city.c_id
LEFT OUTER JOIN firm_address ON m_id = fa_member
LEFT OUTER JOIN city firm_city ON fa_city = firm_city.c_id

WHERE 1 IN (
    SELECT r_id
    FROM region
    INNER JOIN city_region ON r_id = cr_region
    WHERE cr_city = IF(fa_city IS NULL, ha_city, fa_city)
)
SELECT * FROM member

LEFT OUTER JOIN home_address ON m_id = ha_member
LEFT OUTER JOIN city home_city ON ha_city = home_city.c_id
LEFT OUTER JOIN firm_address ON m_id = fa_member
LEFT OUTER JOIN city firm_city ON fa_city = firm_city.c_id

WHERE EXISTS (
    SELECT r_id
    FROM region
    INNER JOIN city_region ON r_id = cr_region
    WHERE cr_city = IF(fa_city IS NULL, ha_city, fa_city)
    AND r_id = 1
)
查询1(错误,缺少成员):

CREATE TABLE `city` (
  `c_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `c_name` varchar(255) NOT NULL DEFAULT '',
  PRIMARY KEY (`c_id`)
);

INSERT INTO `city`
VALUES
  ('1', 'Hillsdale'),
  ('2', 'Smallville'),
  ('3', 'Oakside'),
  ('4', 'Lakeview');

CREATE TABLE `city_region` (
  `cr_city` int(11) unsigned NOT NULL,
  `cr_region` int(11) NOT NULL,
  PRIMARY KEY (`cr_city`,`cr_region`)
);

INSERT INTO `city_region`
VALUES
  ('1', '3'),
  ('2', '1'),
  ('3', '1'),
  ('3', '2'),
  ('4', '1'),
  ('4', '3');

CREATE TABLE `firm_address` (
  `fa_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `fa_member` int(11) NOT NULL,
  `fa_city` int(11) NOT NULL,
  PRIMARY KEY (`fa_id`)
);

INSERT INTO `firm_address`
VALUES
  ('1', '1', '3'),
  ('2', '2', '2'),
  ('3', '3', '1'),
  ('4', '6', '2'),
  ('5', '7', '1');

CREATE TABLE `home_address` (
  `ha_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `ha_member` int(11) NOT NULL,
  `ha_city` int(11) NOT NULL,
  PRIMARY KEY (`ha_id`)
);

INSERT INTO `home_address`
VALUES
  ('1', '1', '2'),
  ('2', '2', '3'),
  ('3', '3', '1'),
  ('4', '4', '1'),
  ('5', '5', '2'),
  ('6', '6', '2');

CREATE TABLE `member` (
  `m_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `m_name` varchar(255) NOT NULL DEFAULT '',
  PRIMARY KEY (`m_id`)
);

INSERT INTO `member`
VALUES
  ('1', 'John'),
  ('2', 'Bob'),
  ('3', 'Dave'),
  ('4', 'Jane'),
  ('5', 'Mary'),
  ('6', 'Karen'),
  ('7', 'Christie');

CREATE TABLE `region` (
  `r_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `r_name` varchar(255) NOT NULL DEFAULT '',
  PRIMARY KEY (`r_id`)
);

INSERT INTO `region`
VALUES
  ('1', 'Central'),
  ('2', 'Lake District'),
  ('3', 'Westside');
SELECT * FROM member

LEFT OUTER JOIN home_address ON m_id = ha_member
LEFT OUTER JOIN city home_city ON ha_city = home_city.c_id
LEFT OUTER JOIN firm_address ON m_id = fa_member
LEFT OUTER JOIN city firm_city ON fa_city = firm_city.c_id

WHERE 1 IN (
    SELECT r_id
    FROM region
    INNER JOIN city_region ON r_id = cr_region
    WHERE cr_city = IF(fa_city IS NULL, ha_city, fa_city)
)
SELECT * FROM member

LEFT OUTER JOIN home_address ON m_id = ha_member
LEFT OUTER JOIN city home_city ON ha_city = home_city.c_id
LEFT OUTER JOIN firm_address ON m_id = fa_member
LEFT OUTER JOIN city firm_city ON fa_city = firm_city.c_id

WHERE EXISTS (
    SELECT r_id
    FROM region
    INNER JOIN city_region ON r_id = cr_region
    WHERE cr_city = IF(fa_city IS NULL, ha_city, fa_city)
    AND r_id = 1
)
查询2(返回正确的结果):

CREATE TABLE `city` (
  `c_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `c_name` varchar(255) NOT NULL DEFAULT '',
  PRIMARY KEY (`c_id`)
);

INSERT INTO `city`
VALUES
  ('1', 'Hillsdale'),
  ('2', 'Smallville'),
  ('3', 'Oakside'),
  ('4', 'Lakeview');

CREATE TABLE `city_region` (
  `cr_city` int(11) unsigned NOT NULL,
  `cr_region` int(11) NOT NULL,
  PRIMARY KEY (`cr_city`,`cr_region`)
);

INSERT INTO `city_region`
VALUES
  ('1', '3'),
  ('2', '1'),
  ('3', '1'),
  ('3', '2'),
  ('4', '1'),
  ('4', '3');

CREATE TABLE `firm_address` (
  `fa_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `fa_member` int(11) NOT NULL,
  `fa_city` int(11) NOT NULL,
  PRIMARY KEY (`fa_id`)
);

INSERT INTO `firm_address`
VALUES
  ('1', '1', '3'),
  ('2', '2', '2'),
  ('3', '3', '1'),
  ('4', '6', '2'),
  ('5', '7', '1');

CREATE TABLE `home_address` (
  `ha_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `ha_member` int(11) NOT NULL,
  `ha_city` int(11) NOT NULL,
  PRIMARY KEY (`ha_id`)
);

INSERT INTO `home_address`
VALUES
  ('1', '1', '2'),
  ('2', '2', '3'),
  ('3', '3', '1'),
  ('4', '4', '1'),
  ('5', '5', '2'),
  ('6', '6', '2');

CREATE TABLE `member` (
  `m_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `m_name` varchar(255) NOT NULL DEFAULT '',
  PRIMARY KEY (`m_id`)
);

INSERT INTO `member`
VALUES
  ('1', 'John'),
  ('2', 'Bob'),
  ('3', 'Dave'),
  ('4', 'Jane'),
  ('5', 'Mary'),
  ('6', 'Karen'),
  ('7', 'Christie');

CREATE TABLE `region` (
  `r_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `r_name` varchar(255) NOT NULL DEFAULT '',
  PRIMARY KEY (`r_id`)
);

INSERT INTO `region`
VALUES
  ('1', 'Central'),
  ('2', 'Lake District'),
  ('3', 'Westside');
SELECT * FROM member

LEFT OUTER JOIN home_address ON m_id = ha_member
LEFT OUTER JOIN city home_city ON ha_city = home_city.c_id
LEFT OUTER JOIN firm_address ON m_id = fa_member
LEFT OUTER JOIN city firm_city ON fa_city = firm_city.c_id

WHERE 1 IN (
    SELECT r_id
    FROM region
    INNER JOIN city_region ON r_id = cr_region
    WHERE cr_city = IF(fa_city IS NULL, ha_city, fa_city)
)
SELECT * FROM member

LEFT OUTER JOIN home_address ON m_id = ha_member
LEFT OUTER JOIN city home_city ON ha_city = home_city.c_id
LEFT OUTER JOIN firm_address ON m_id = fa_member
LEFT OUTER JOIN city firm_city ON fa_city = firm_city.c_id

WHERE EXISTS (
    SELECT r_id
    FROM region
    INNER JOIN city_region ON r_id = cr_region
    WHERE cr_city = IF(fa_city IS NULL, ha_city, fa_city)
    AND r_id = 1
)
如果您能帮助理解这种不一致性,我们将不胜感激


谢谢。

我今天花了一些时间研究这个问题,它似乎是MySQL 5.6中的一个bug。(我还测试了MySQL 5.6.15,得到了相同的结果。)

MySQL 5.6在执行此查询时使用了一些新的优化,但它们似乎并不是造成差异的原因,因为这无助于设置,例如:

set session optimizer_switch="block_nested_loop=off";

使用
IFNULL(fa_city,ha_city)
而不是
IF(fa_city为NULL,hau city,fau city)
确实会产生正确的结果,因此错误似乎在WHERE子句的子查询中处理
IF()

r_id
是否为NULL?请编辑您的查询,使其具有表别名。无法判断列的来源。这两个查询给出了相同的结果,请查看此演示:结果在v5.5中相同,但在5.6中不同,更新的问题澄清了这一点。感谢您指出这一点,我认为它更多地与
IF()
函数有关,而不是与
中的
运算符有关。我将
WHERE cr_city=IF(fa_city为NULL,ha_city,fa_city)
更改为
WHERE cr_city=IFNULL(fa_city,ha_city)
它开始在两个版本中工作。您还应该检查它是否在最新版本的MYSQL 5.6(目前为5.6.15)中工作,在SqlFIDLE上有5.6.6)Jeremy。谢谢你看这个。我将向mysql提交一张罚单,并在等待期结束时奖励赏金。您是否在中创建了错误罚单?如果是,我可以看到它的URL吗?