Mysql 分组或添加

我只想得到一行日期：

select Datum, ZONE_2, 0 as SEEFRACHT

        from (

             select to_char(arch_p.ANKUEND_TERMIN,'dd.mm.yy') as Datum, Count (*) as ZONE_2
             from ARCH_PACKSTUECK arch_p
             where (arch_p.lbr_auf_nr like '%02')
             group by to_char(arch_p.ANKUEND_TERMIN,'dd.mm.yy')

             union all

             select to_char(ANKUEND_TERMIN,'dd.mm.yy') as Datum, Count (*) as ZONE_2
             from PACKSTUECK p
             where(p.lbr_auf_nr like '%02')
             group by to_char(p.ANKUEND_TERMIN,'dd.mm.yy')

             order by Datum           
             )

试试这个

select Datum, sum(ZONE_2) as ZONE_2, 0 as SEEFRACHT
        from (

             select to_char(arch_p.ANKUEND_TERMIN,'dd.mm.yy') as Datum, Count (*) as ZONE_2
             from ARCH_PACKSTUECK arch_p
             where (arch_p.lbr_auf_nr like '%02')
             group by to_char(arch_p.ANKUEND_TERMIN,'dd.mm.yy')

             union all

             select to_char(ANKUEND_TERMIN,'dd.mm.yy') as Datum, Count (*) as ZONE_2
             from PACKSTUECK p
             where(p.lbr_auf_nr like '%02')
             group by to_char(p.ANKUEND_TERMIN,'dd.mm.yy')

             ) as t
        group by Datum           
        order by Datum           

看见

select Datum, sum(ZONE_2) as ZONE_2, 0 as SEEFRACHT
        from (

             select to_char(arch_p.ANKUEND_TERMIN,'dd.mm.yy') as Datum, Count (*) as ZONE_2
             from ARCH_PACKSTUECK arch_p
             where (arch_p.lbr_auf_nr like '%02')
             group by to_char(arch_p.ANKUEND_TERMIN,'dd.mm.yy')

             union all

             select to_char(ANKUEND_TERMIN,'dd.mm.yy') as Datum, Count (*) as ZONE_2
             from PACKSTUECK p
             where(p.lbr_auf_nr like '%02')
             group by to_char(p.ANKUEND_TERMIN,'dd.mm.yy')

             ) as t
        group by Datum           
        order by Datum