mysql求和函数问题
我对mysql中的SUM()函数有一些疑问。当我在没有条件的情况下使用SUM()函数时,它可以正常工作。但如果我将SUM()函数与条件一起使用,它将返回与条件匹配的记录数。给我解释一下 我创建了一个包含四列的表格教师,如下所示mysql求和函数问题,mysql,aggregate-functions,Mysql,Aggregate Functions,我对mysql中的SUM()函数有一些疑问。当我在没有条件的情况下使用SUM()函数时,它可以正常工作。但如果我将SUM()函数与条件一起使用,它将返回与条件匹配的记录数。给我解释一下 我创建了一个包含四列的表格教师,如下所示 mysql> desc Teacher; +--------------+-------------+------+-----+-------------------+ | Field | Type | Null | Key | De
mysql> desc Teacher;
+--------------+-------------+------+-----+-------------------+
| Field | Type | Null | Key | Default |
+--------------+-------------+------+-----+-------------------+
| TeacherId | varchar(36) | NO | PRI | NULL |
| FirstName | varchar(50) | NO | | NULL |
| LastName | varchar(50) | NO | | NULL |
| SyncStatus | int(11) | NO | | NULL |
+--------------+-------------+------+-----+-------------------+
它包含以下记录。
mysql> select * from Teacher;
+-----------+-----------+-----------+------------+
| TeacherId | FirstName | LastName | SyncStatus |
+-----------+-----------+-----------+------------+
| 001 | Sagar | Kapadia | 1 |
| 002 | Vishal | Chaudhari | 1 |
| 003 | Milan | Panchal | 1 |
| 004 | Jugal | Desai | 1 |
| 005 | Baburao | Apte | 1 |
| 006 | Jaya | Bacchan | 0 |
| 007 | Jaya | Bacchan | 2 |
| 008 | Jaya | Bacchan | 2 |
+-----------+-----------+-----------+------------+
8 rows in set (0.00 sec)
mysql> select TeacherId,FirstName,LastName,Concat(FirstName,' ',LastName) as FullName,SUM(SyncStatus) from Teacher having FullName like '_____ %';
+-----------+-----------+----------+---------------+-----------------+
| TeacherId | FIrstName | LastName | FullName | sum(SyncStatus) |
+-----------+-----------+----------+---------------+-----------------+
| 001 | Sagar | Kapadia | Sagar Kapadia | 9 |
+-----------+-----------+----------+---------------+-----------------+
1 row in set (0.00 sec)
mysql> select TeacherId,FIrstName,LastName,Concat(FirstName,' ',LastName) as FullName,sum(SyncStatus = 0) from Teacher having FullName like '_____ %';
+-----------+-----------+----------+---------------+---------------------+
| TeacherId | FIrstName | LastName | FullName | sum(SyncStatus = 0) |
+-----------+-----------+----------+---------------+---------------------+
| 001 | Sagar | Kapadia | Sagar Kapadia | 1 |
+-----------+-----------+----------+---------------+---------------------+
1 row in set (0.00 sec)
mysql> select TeacherId,FIrstName,LastName,Concat(FirstName,' ',LastName) as FullName,sum(SyncStatus = 1) from Teacher having FullName like '_____ %';
+-----------+-----------+----------+---------------+---------------------+
| TeacherId | FIrstName | LastName | FullName | sum(SyncStatus = 1) |
+-----------+-----------+----------+---------------+---------------------+
| 001 | Sagar | Kapadia | Sagar Kapadia | 5 |
+-----------+-----------+----------+---------------+---------------------+
1 row in set (0.00 sec)
mysql> select TeacherId,FIrstName,LastName,Concat(FirstName,' ',LastName) as FullName,sum(SyncStatus = 2) from Teacher having FullName like '_____ %';
+-----------+-----------+----------+---------------+---------------------+
| TeacherId | FIrstName | LastName | FullName | sum(SyncStatus = 2) |
+-----------+-----------+----------+---------------+---------------------+
| 001 | Sagar | Kapadia | Sagar Kapadia | 2 |
+-----------+-----------+----------+---------------+---------------------+
1 row in set (0.00 sec)
因此它将在同步状态下返回完美的总和。但如果我将SUM()与条件一起使用,则返回记录数。
mysql> select * from Teacher;
+-----------+-----------+-----------+------------+
| TeacherId | FirstName | LastName | SyncStatus |
+-----------+-----------+-----------+------------+
| 001 | Sagar | Kapadia | 1 |
| 002 | Vishal | Chaudhari | 1 |
| 003 | Milan | Panchal | 1 |
| 004 | Jugal | Desai | 1 |
| 005 | Baburao | Apte | 1 |
| 006 | Jaya | Bacchan | 0 |
| 007 | Jaya | Bacchan | 2 |
| 008 | Jaya | Bacchan | 2 |
+-----------+-----------+-----------+------------+
8 rows in set (0.00 sec)
mysql> select TeacherId,FirstName,LastName,Concat(FirstName,' ',LastName) as FullName,SUM(SyncStatus) from Teacher having FullName like '_____ %';
+-----------+-----------+----------+---------------+-----------------+
| TeacherId | FIrstName | LastName | FullName | sum(SyncStatus) |
+-----------+-----------+----------+---------------+-----------------+
| 001 | Sagar | Kapadia | Sagar Kapadia | 9 |
+-----------+-----------+----------+---------------+-----------------+
1 row in set (0.00 sec)
mysql> select TeacherId,FIrstName,LastName,Concat(FirstName,' ',LastName) as FullName,sum(SyncStatus = 0) from Teacher having FullName like '_____ %';
+-----------+-----------+----------+---------------+---------------------+
| TeacherId | FIrstName | LastName | FullName | sum(SyncStatus = 0) |
+-----------+-----------+----------+---------------+---------------------+
| 001 | Sagar | Kapadia | Sagar Kapadia | 1 |
+-----------+-----------+----------+---------------+---------------------+
1 row in set (0.00 sec)
mysql> select TeacherId,FIrstName,LastName,Concat(FirstName,' ',LastName) as FullName,sum(SyncStatus = 1) from Teacher having FullName like '_____ %';
+-----------+-----------+----------+---------------+---------------------+
| TeacherId | FIrstName | LastName | FullName | sum(SyncStatus = 1) |
+-----------+-----------+----------+---------------+---------------------+
| 001 | Sagar | Kapadia | Sagar Kapadia | 5 |
+-----------+-----------+----------+---------------+---------------------+
1 row in set (0.00 sec)
mysql> select TeacherId,FIrstName,LastName,Concat(FirstName,' ',LastName) as FullName,sum(SyncStatus = 2) from Teacher having FullName like '_____ %';
+-----------+-----------+----------+---------------+---------------------+
| TeacherId | FIrstName | LastName | FullName | sum(SyncStatus = 2) |
+-----------+-----------+----------+---------------+---------------------+
| 001 | Sagar | Kapadia | Sagar Kapadia | 2 |
+-----------+-----------+----------+---------------+---------------------+
1 row in set (0.00 sec)
你说得对。此函数
sum(SyncStatus=2)
将返回行数,因为这就是它的执行方式
在每一行中,
SyncStatus=2
将测试SyncStatus是否等于2
,并返回1(真)或0(假)
,因此您基本上得到了真值的总和(1)谢谢@Ankur。我现在了解了SUM()函数将如何执行。再次感谢你……刚刚遇到了这种事情——它看起来像是在做我想做的事情(使用SUM(confirmed=1)
和groupby
)返回一个月内完成操作的次数,但我不确定它是否应该这样做——现在我知道了:)