Mysql 计数（不同的'goodfor_what`.'name`）=3会导致错误消息

我收到了错误信息

您的SQL语法有错误；检查手册 对应于您的MySQL服务器版本，以便使用正确的语法 当.name=1时，具有COUNTDISTINCT goodfor_的近组名称

下面是发生错误的查询的一部分

                    ....
        WHERE 
        ( `city`.`name` = "London" ) AND 
        `goodfor_what`.`name` IN ("Beers","Wine","Food") 
        GROUP BY name 

        HAVING COUNT(DISTINCT `goodfor_what`.`name`) = 3 AND `goodfor_when`.`name` IN ('Daytime') GROUP BY name
        HAVING COUNT(DISTINCT `goodfor_when`.`name`) = 1 ORDER BY `t`.`name`, `t`.`id`;

但是，如果删除该行，则该操作有效

HAVING COUNT(DISTINCT `goodfor_what`.`name`) = 3 AND `goodfor_when`.`name` IN ('Daytime') GROUP BY name

同一查询中不能有两个HAVING或两个GROUP BY命令，GROUP BY必须放在HAVING之前。例如：

GROUP BY name
HAVING (COUNT(DISTINCT `goodfor_what`.`name`) = 3 AND `goodfor_when`.`name` IN ('Daytime'))
OR COUNT(DISTINCT `goodfor_when`.`name`) = 1 
ORDER BY `t`.`name`, `t`.`id`;

此外，除非t.id是聚合列，否则如果要按t.id排序，则必须选择t.id和GROUP BY t.id。同一查询中不能有两个HAVING或两个GROUP BY命令，并且GROUP BY必须放在HAVING之前。例如：

GROUP BY name
HAVING (COUNT(DISTINCT `goodfor_what`.`name`) = 3 AND `goodfor_when`.`name` IN ('Daytime'))
OR COUNT(DISTINCT `goodfor_when`.`name`) = 1 
ORDER BY `t`.`name`, `t`.`id`;

此外，除非t.id是聚合列，否则如果要按t.id排序，就必须选择t.id和GROUP BY t.id