mysql选择id，其中列匹配所有值

我有一张桌子：

id  filter_id
1   5
2   5
3   5
3   17
4   17
5   17

ID不是唯一的

我需要像这样的东西

SELECT id FROM table WHERE filter = 5 AND filter = 17

但它不返回任何内容，因为筛选器列不能同时为5和17

所以我需要得到id=3的结果

我试过了

SELECT id FROM table WHERE filter IN (5, 17)

但我需要和，而不是手术

谢谢您的帮助。

您可以使用：

SELECT  id
FROM table
WHERE filter IN (5,17)
GROUP BY id
HAVING COUNT(DISTINCT filter) = 2

您可以使用：

SELECT  id
FROM table
WHERE filter IN (5,17)
GROUP BY id
HAVING COUNT(DISTINCT filter) = 2

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另一种使用

sum

SELECT  id
FROM table
GROUP BY id
HAVING SUM(filter = 5)
and SUM(filter = 17)

---

另一种使用

sum

SELECT  id
FROM table
GROUP BY id
HAVING SUM(filter = 5)
and SUM(filter = 17)

---

不分组数据，以防表中有太多行：

SELECT distinct id FROM table t1 WHERE filter_id = 5 and exists (select 1 from table t2 where filter_id = 17 and t1.id = t2.id);

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不分组数据，以防表中有这么多行：

SELECT distinct id FROM table t1 WHERE filter_id = 5 and exists (select 1 from table t2 where filter_id = 17 and t1.id = t2.id);