Mysql 从多个表中获取多个值

我在MySQL中设置了一个数据库，有两个不同的表：

表“匹配项”

表“团队”

我希望能够将表“matches”中的id与表“teams”中的团队名称关联起来，这样我就可以在匹配页面上打印出来

我的问题是，我不能根据自己的需要回答这个问题

我的最新尝试：

SELECT matches.*, teams.name AS team1name
FROM matches
LEFT JOIN teams ON matches.team1ID = teams.id
UNION
SELECT matches.*, teams.name AS team2name
FROM matches
LEFT JOIN teams ON matches.team2ID = teams.id

这显然不理想，因为我两次获得所有匹配数据。
这给了我两个名称，但它们位于不同的行上，并且都标记为

team1name

我希望得到的结果是：

ID TEAM1ID   TEAM2ID  TIME   DATE   TEAM1NAME   TEAM2NAME
---------------------------------------------------------
5  13        14       21:00  5 May  GucciGang   BeachBoys

---

这可能吗？

只需将表连接两次：

SELECT    matches.*
,         Team1.name AS team1name
,         Team2.name AS team2name
FROM      matches
LEFT JOIN teams AS Team1
       ON matches.team1ID = Team1.id
LEFT JOIN teams AS Team2
       ON matches.team2ID = Team2.id

注意：最好是专门指定列，而不是

SELECT*

ID TEAM1ID   TEAM2ID  TIME   DATE   TEAM1NAME   TEAM2NAME
---------------------------------------------------------
5  13        14       21:00  5 May  GucciGang   BeachBoys

SELECT    matches.*
,         Team1.name AS team1name
,         Team2.name AS team2name
FROM      matches
LEFT JOIN teams AS Team1
       ON matches.team1ID = Team1.id
LEFT JOIN teams AS Team2
       ON matches.team2ID = Team2.id