在Neo4j中，如何在Cypher查询语言中使用类似SQL的GROUP BY？

我想找出一家公司所有用户的数量，以及该公司男女用户的数量。我的问题是：

 start n=node:company(name:"comp")
 match n<-[:Members_In]-x, n<-[:Members_In]-y  
 where x.Sex='Male' and y.Sex='Female' 
 return n.name as companyName, count(distinct x) as NumOfMale,
 count(distinct y) as NumOfFemale" );

start n=节点：公司（名称：“comp”）
匹配n尝试

start n=node:node\u auto\u index（name='comp'）
匹配n尝试

start n=node:node\u auto\u index（name='comp'）
匹配nPeter在此处创建了一个叉积：

我认为这更适合您的用例

start n=node:node_auto_index(name='comp')
match n<-[:Members_In]-x
with  n.name as companyName, collect(x) as employees
return length(filter(x in employees : x.Sex='Male')) as NumOfMale,
length(filter(x in employees : x.Sex='Female')) as NumOfFemale,
length(employees) as Total

start n=node:node\u auto\u index（name='comp'）
匹配nPeter在此处创建了一个叉积：

我认为这更适合您的用例

start n=node:node_auto_index(name='comp')
match n<-[:Members_In]-x
with  n.name as companyName, collect(x) as employees
return length(filter(x in employees : x.Sex='Male')) as NumOfMale,
length(filter(x in employees : x.Sex='Female')) as NumOfFemale,
length(employees) as Total

start n=node:node\u auto\u index（name='comp'）
匹配n实际上有一种更简单的方法来实现这个结果

START n=node:node_auto_index(name='comp') 
MATCH n<-[:Members_In]-x 
RETURN count(x.name), x.Sex

START n=node:node\u auto\u index（name='comp'）
匹配n实际上有一种更简单的方法来实现这个结果

START n=node:node_auto_index(name='comp') 
MATCH n<-[:Members_In]-x 
RETURN count(x.name), x.Sex

START n=node:node\u auto\u index（name='comp'）
匹配