Neo4j 在与聚合和多个order by子句匹配后创建关系

跟进问题

我现在需要创建一个站点和一个邻居（位于中）之间的关系。第一个查询成功地为每个站点返回1行（1个组合）。我想要创建关系的第二个查询创建了太多的关系

MATCH (n:Neighborhood),(s:Station)
WITH n, s, distance(n.centerLocation, s.point) AS dist
ORDER BY dist
RETURN s.stationId, COLLECT(n)[0].name AS name, COLLECT(dist)[0] AS shortest
ORDER BY s.stationId

查询2:

MATCH (n:Neighborhood),(s:Station)
WITH n, s, distance(n.centerLocation, s.point) AS dist
ORDER BY dist
CREATE (s)-[r:LOCATED_IN]->(nbh)
RETURN s.stationId, COLLECT(n)[0] AS nbh, COLLECT(dist)[0] AS shortest
ORDER BY s.stationId

MATCH (n:Neighborhood),(s:Station)
WITH n, s, distance(n.centerLocation, s.point) AS dist
ORDER BY dist
CREATE (s)-[r:LOCATED_IN]->(n)
RETURN s.stationId, COLLECT(n)[0] AS nbh, COLLECT(dist)[0] AS shortest
ORDER BY s.stationId

查询3:

MATCH (n:Neighborhood),(s:Station)
WITH n, s, distance(n.centerLocation, s.point) AS dist
ORDER BY dist
CREATE (s)-[r:LOCATED_IN]->(nbh)
RETURN s.stationId, COLLECT(n)[0] AS nbh, COLLECT(dist)[0] AS shortest
ORDER BY s.stationId

MATCH (n:Neighborhood),(s:Station)
WITH n, s, distance(n.centerLocation, s.point) AS dist
ORDER BY dist
CREATE (s)-[r:LOCATED_IN]->(n)
RETURN s.stationId, COLLECT(n)[0] AS nbh, COLLECT(dist)[0] AS shortest
ORDER BY s.stationId

查询2后： 站点（蓝色节点）连接到不表示邻域节点的多个节点。他们只有身份证。

查询3后： 站点（蓝色节点）连接到多个邻居节点。每个车站应该只有一个街区。

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我应该如何编写查询以使每个站点有一个邻居？查询2有缺陷，因为

CREATE

使用了未绑定的

nbh

变量

对于查询3，您需要创建一个从每个站点到最近的单个邻居的关系。例如：

MATCH (n:Neighborhood), (s:Station)
WITH n, s, distance(n.centerLocation, s.point) AS dist
ORDER BY dist
WITH s, COLLECT(dist)[0] AS shortest, COLLECT(n)[0] AS nbh
CREATE (s)-[:LOCATED_IN]->(nbh)
RETURN s.stationId, nbh, shortest
ORDER BY s.stationId

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这给了我同样的结果（查询3，图2）Oops。修好了。