Node.js 在“巴士男孩”活动(完成)中,我可以';无法获取file.pipe.object结果
例如:Node.js 在“巴士男孩”活动(完成)中,我可以';无法获取file.pipe.object结果,node.js,busboy,Node.js,Busboy,例如: 1.Test1.txt其base64:VGhpcyBpcyB0ZXN0MS4= 2.Test2.txt其base64:vghpcybpcybuzzn0mi4= 我的代码: var busboy = new Busboy({ headers: req.headers }); var base64data = []; busboy.on('file', function(fieldname, file, filename, encoding, mimetype) { var outp
1.Test1.txt其base64:VGhpcyBpcyB0ZXN0MS4=
2.Test2.txt其base64:vghpcybpcybuzzn0mi4=
我的代码:
var busboy = new Busboy({ headers: req.headers });
var base64data = [];
busboy.on('file', function(fieldname, file, filename, encoding, mimetype) {
var output = stream.PassThrough();
var chunk = [];
console.log('File: ' + filename + ', mimetype: ' + mimetype);
file.pipe(base64.encode()).pipe(output);
output.on('data', function(data) {
chunk.push(data);
console.log('Chunk: ' + chunk);
});
output.on('end', function(){
base64data.push(Buffer.concat(chunk));
console.log('Data1: ' + base64data);
});
}).on('finish', function(){
console.log('Data2: ' + base64data);
})
输出:
File: Test1.txt, mimetype: text/plain
File: Test2.txt, mimetype: text/plain
Chunk: VGhpcyBpcyB0ZXN0
Chunk: VGhpcyBpcyBUZXN0
Chunk: VGhpcyBpcyB0ZXN0,MS4=
Chunk: VGhpcyBpcyBUZXN0,Mi4=
Data2:
Data1: VGhpcyBpcyB0ZXN0MS4=
Data1: VGhpcyBpcyB0ZXN0MS4=,VGhpcyBpcyBUZXN0Mi4=
为什么数据2是空的?如何修改此代码?请帮忙!谢谢~
我尝试在file.event(data)中使用Buffer.toString('base64'),但它只能转换文本内容,图片无法转换?您不需要这些额外的流。但问题是,额外的流结束事件在下一个滴答声中发出(因此,在巴士司机的
完成
事件之后)
您应该能够将代码简化为:
var busboy = new Busboy({ headers: req.headers });
var base64data = [];
busboy.on('file', function(fieldname, file, filename, encoding, mimetype) {
console.log('File: ' + filename + ', mimetype: ' + mimetype);
var buffer = '';
file.setEncoding('base64');
file.on('data', function(data) {
// `data` is now a base64-encoded chunk of file data
buffer += data;
}).on('end', function() {
base64data.push(buffer);
});
}).on('finish', function(){
console.log('Data2: ' + base64data);
})
我明白了~非常感谢