Node.js 在中间件expressjs/nodejs中传递参数
我在nodeJS项目中工作,我想在中间件中传递param,以便在代码中进行验证 例如,我创建的中间件如下所示Node.js 在中间件expressjs/nodejs中传递参数,node.js,express,Node.js,Express,我在nodeJS项目中工作,我想在中间件中传递param,以便在代码中进行验证 例如,我创建的中间件如下所示 'use strict'; // eslint-disable-next-line no-unused-vars import BadRequest from '../../../errors/BadRequest'; // eslint-disable-next-line no-unused-vars import ResponseFormatter from '../../../ut
'use strict';
// eslint-disable-next-line no-unused-vars
import BadRequest from '../../../errors/BadRequest';
// eslint-disable-next-line no-unused-vars
import ResponseFormatter from '../../../util/ResponseFormatter';
export default function middlewareWithParam (options) {
return function (req, res, next) {
// Implement the middleware function based on the options object
return next();
//ResponseFormatter.error(new BadRequest('03'), req, res);
};
}
现在,我希望在控制器类中使用该中间件,以便通过在每个端点传递不同的值,中间件可以验证请求
例如
但我得到了一个错误
'middlewares': [(0, _middlewareWithParam.middlewareWithParam)()],
^
TypeError: (0 , _middlewareWithParam.middlewareWithParam) is not a function
没有必要对其进行分解。拆下卷曲支架。改变
import { middlewareWithParam } from '../middlewares/validators/Role/middlewareWithParam';
到
看看
编辑:
或者做类似的事情来定义它
function middlewareWithParam(options) {
return function(req, res, next) {
// return next();
};
}
module.exports = {
middlewareWithParam
}
或者删除默认值
export function middlewareWithParam(options) {
return function(req, res, next) {
// return next();
};
}
function middlewareWithParam(options) {
return function(req, res, next) {
// return next();
};
}
module.exports = {
middlewareWithParam
}
export function middlewareWithParam(options) {
return function(req, res, next) {
// return next();
};
}