Objective c 另一个EXC\u坏访问

我修复了上一个问题的错误，但我的代码引发了另一个EXC\u BAD\u访问

在

完整的代码是

sqlite3 *database;
// Setup some globals
NSString *databaseName = @"test.sql";

// Get the path to the documents directory and append the databaseName
NSArray *documentPaths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
NSString *documentsDir = [documentPaths objectAtIndex:0];
NSString * databasePath = [documentsDir stringByAppendingPathComponent:databaseName];
[databasePath retain];
sqlite3_stmt *compiledStatement;

NSString * TheNewText = self.animalDesciption.text; 
[TheNewText retain];

NSString * the_user = AnimalName ;
[ the_user retain];

NSString *NewData = [NSString stringWithFormat:@"%@%@%@%@", @"Update animals set description = ",TheNewText , " Where name =  ",the_user];

[NewData retain] ;

if(sqlite3_open([databasePath UTF8String], &database) == SQLITE_OK) {

    const char *sqlStatement = [NewData UTF8String];



    if(sqlite3_prepare_v2(database, sqlStatement, -1, &compiledStatement, NULL)== SQLITE_OK) {

        sqlite3_reset(sqlStatement);
    }

---

我敢打赌字符串是通过自动释放运行收集的。在文档中查找UTF8String，他们建议复制该字符串以确保其持续时间超过该点

经过深思熟虑后，我真正的建议是去掉对垫脚石变量的赋值

我想说，像这样使用它：

if(sqlite3_prepare_v2(database, [NewData UTF8String], -1, &compiledStatement, NULL)== SQLITE_OK) {

        sqlite3_reset(compiledStatement);

---

注意重置语句中的更改。这可能是您真正的问题，您的代码试图执行一个字符串而不是一个准备好的sqlite语句。

您是否尝试过alloc和init NSString

NSString *NewData = [[NSString alloc] initWithFormat:@"%@%@%@%@", @"Update animals set description = ",TheNewText , " Where name =  ",the_user];

---

不要留着吗？

请给我更多的插图好吗

NSString *NewData = [[NSString alloc] initWithFormat:@"%@%@%@%@", @"Update animals set description = ",TheNewText , " Where name =  ",the_user];