Objective c 如何对NSMutableArray重复值进行计数和排序
我看到了这个问题:Objective c 如何对NSMutableArray重复值进行计数和排序,objective-c,sorting,nsmutablearray,nsarray,Objective C,Sorting,Nsmutablearray,Nsarray,我看到了这个问题: 这个解决方案非常接近我所需要的 我指的解决方案是: NSInteger countedSort(id obj1, id obj2, void *context) { NSCountedSet *countedSet = context; NSUInteger obj1Count = [countedSet countForObject:obj1]; NSUInteger obj2Count = [countedSet countForObject:obj2
这个解决方案非常接近我所需要的 我指的解决方案是:
NSInteger countedSort(id obj1, id obj2, void *context) {
NSCountedSet *countedSet = context;
NSUInteger obj1Count = [countedSet countForObject:obj1];
NSUInteger obj2Count = [countedSet countForObject:obj2];
if (obj1Count > obj2Count) return NSOrderedAscending;
else if (obj1Count < obj2Count) return NSOrderedDescending;
return NSOrderedSame;
}
排序按计数返回正确的排序数组,但我需要将计数包括在内或包含在另一个按升序排序的数组中。解决方案可以是简单地查询任何对象的计数的计数集,以构建跟踪计数的数组:
// This after having sorted the array:
NSMutableArray* counts= [NSMutableArray arrayWithCapacity: array.count];
for(id object in array) {
[counts addObject: @([countedSet countForObject: object]) ];
}
解决方案可以是简单地查询任何对象的计数集,以构建跟踪计数的数组:
// This after having sorted the array:
NSMutableArray* counts= [NSMutableArray arrayWithCapacity: array.count];
for(id object in array) {
[counts addObject: @([countedSet countForObject: object]) ];
}
这将返回按最常出现的值排序的排序数组
NSCountedSet *countedSet = [[NSCountedSet alloc] initWithArray:array];
NSArray *sortedValues = [countedSet.allObjects sortedArrayUsingComparator:^(id obj1, id obj2) {
NSUInteger n = [countedSet countForObject:obj1];
NSUInteger m = [countedSet countForObject:obj2];
return (n <= m)? (n < m)? NSOrderedDescending : NSOrderedSame : NSOrderedAscending;
}];
NSCountedSet*countedSet=[[NSCountedSet alloc]initWithArray:array];
NSArray*sortedValues=[countedSet.AllObject SortedArray使用比较器:^(id obj1,id obj2){
NSUN整数=[countedSet countForObject:obj1];
NSUM整数=[countedSet countForObject:obj2];
return(n此返回按最常出现的值排序的排序数组
NSCountedSet *countedSet = [[NSCountedSet alloc] initWithArray:array];
NSArray *sortedValues = [countedSet.allObjects sortedArrayUsingComparator:^(id obj1, id obj2) {
NSUInteger n = [countedSet countForObject:obj1];
NSUInteger m = [countedSet countForObject:obj2];
return (n <= m)? (n < m)? NSOrderedDescending : NSOrderedSame : NSOrderedAscending;
}];
NSCountedSet*countedSet=[[NSCountedSet alloc]initWithArray:array];
NSArray*sortedValues=[countedSet.AllObject SortedArray使用比较器:^(id obj1,id obj2){
NSUN整数=[countedSet countForObject:obj1];
NSUM整数=[countedSet countForObject:obj2];
返回(n)一个简单的解决方案。谢谢!一个简单的解决方案。谢谢!