Odoo 如何在create中获得客户发送给帮助台的第一封电子邮件

我在我的非奥多网站上有一个联系表，可以向我的奥多帮助台电子邮件别名发送电子邮件。因为电子邮件是从我的网站发送的，“发件人”电子邮件是“否”-reply@mydomain.com“而不是客户在服务台发电子邮件。客户电子邮件位于发送到帮助台的第一封电子邮件的正文中。是否可以在

helpdesk_ticket.py

中的

create

方法中检索发送到帮助台的第一封邮件/电子邮件

@api.model_create_multi
def create(self, list_value):
    now = fields.Datetime.now()
    # determine user_id and stage_id if not given. Done in batch.
    teams = self.env['helpdesk.team'].browse([vals['team_id'] for vals in list_value if vals.get('team_id')])
    team_default_map = dict.fromkeys(teams.ids, dict())
    for team in teams:
        team_default_map[team.id] = {
            'stage_id': team._determine_stage()[team.id].id,
            'user_id': team._determine_user_to_assign()[team.id].id
        }
        
    _logger.info("in create");    
    _logger.info(list_value); 
    # Manually create a partner now since 'generate_recipients' doesn't keep the name. This is
    # to avoid intrusive changes in the 'mail' module
    for vals in list_value:
        partner_id = vals.get('partner_id', False)
        partner_name = vals.get('partner_name', False)
        partner_email = vals.get('partner_email', False)
        if partner_name and partner_email and not partner_id:
            try:
                vals['partner_id'] = self.env['res.partner'].find_or_create(
                    tools.formataddr((partner_name, partner_email))
                )
            except UnicodeEncodeError:
                # 'formataddr' doesn't support non-ascii characters in email. Therefore, we fall
                # back on a simple partner creation.
                vals['partner_id'] = self.env['res.partner'].create({
                    'name': partner_name,
                    'email': partner_email,
                }).id

    # determine partner email for ticket with partner but no email given
    partners = self.env['res.partner'].browse([vals['partner_id'] for vals in list_value if 'partner_id' in vals and vals.get('partner_id') and 'partner_email' not in vals])
    partner_email_map = {partner.id: partner.email for partner in partners}
    partner_name_map = {partner.id: partner.name for partner in partners}

    for vals in list_value:
        if vals.get('team_id'):
            team_default = team_default_map[vals['team_id']]
            if 'stage_id' not in vals:
                vals['stage_id'] = team_default['stage_id']
            # Note: this will break the randomly distributed user assignment. Indeed, it will be too difficult to
            # equally assigned user when creating ticket in batch, as it requires to search after the last assigned
            # after every ticket creation, which is not very performant. We decided to not cover this user case.
            if 'user_id' not in vals:
                vals['user_id'] = team_default['user_id']
            if vals.get('user_id'):  # if a user is finally assigned, force ticket assign_date and reset assign_hours
                vals['assign_date'] = fields.Datetime.now()
                vals['assign_hours'] = 0

        # set partner email if in map of not given
        if vals.get('partner_id') in partner_email_map:
            vals['partner_email'] = partner_email_map.get(vals['partner_id'])
        # set partner name if in map of not given
        if vals.get('partner_id') in partner_name_map:
            vals['partner_name'] = partner_name_map.get(vals['partner_id'])

        if vals.get('stage_id'):
            vals['date_last_stage_update'] = now

    # context: no_log, because subtype already handle this
    tickets = super(Ticket, self).create(list_value)

    # make customer follower
    for ticket in tickets:
        if ticket.partner_id:
            ticket.message_subscribe(partner_ids=ticket.partner_id.ids)

        ticket._portal_ensure_token()

    # apply SLA
    tickets.sudo()._sla_apply()

    return tickets