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Oop PDO从类方法返回$row_Oop_Methods_Pdo - Fatal编程技术网

Oop PDO从类方法返回$row

Oop PDO从类方法返回$row,oop,methods,pdo,Oop,Methods,Pdo,嘿,伙计们,我正在学习php中的OOP。当我试图在自己的类中定制PDO时,我遇到了一些问题。基本上,我已经尝试返回行,并在我的课堂外获取它。不幸的是,我不会工作。我对非对象上的成员函数fetch进行了此错误调用。看一看,如果可以的话给我一些建议。非常感谢 $connection = new MySql(DBUSER, DBPASS); $row = $connection->query("select * from users", "name"); while($row->fetch

嘿,伙计们,我正在学习php中的OOP。当我试图在自己的类中定制PDO时,我遇到了一些问题。基本上,我已经尝试返回行,并在我的课堂外获取它。不幸的是,我不会工作。我对非对象上的成员函数fetch进行了此错误调用。看一看,如果可以的话给我一些建议。非常感谢

$connection = new MySql(DBUSER, DBPASS);
$row = $connection->query("select * from users", "name");
while($row->fetch(PDO::FETCH_ASSOC)){
    echo "<p>". $row["name"] ."</p>";
}
下面是MySql类的外观:

class MySql{
    private $dbc;
    private $user;
    private $pass;

    function __construct($user="root", $pass=""){
    $this->user = $user;
    $this->pass = $pass;    
    try{
       $this->dbc = new PDO("mysql:host=localhost; dbname=DBNAME;charset=utf8", $user, $pass);
        }
    catch(PDOException $e){
       echo $e->getMessage();
       echo "Problem z Połączeniem do MySql sprawdź haslo i uzytkownika";
        }
    }
    public function query($query, $c1=""){
    $mysqlquery = $this->dbc->prepare($query);
    $mysqlquery->execute();
    return $row = $mysqlquery->fetch(PDO::FETCH_ASSOC);
    /* I WANT TO PERFORM COMENTED CODE OUTSIDE THE CLASS
    while($row = $mysqlquery->fetch(PDO::FETCH_ASSOC)){
        if($c1!=""){
        echo "<p>". $row[$c1] ."</p>";
        }
    }
    */
}
如果要返回$mysqlquery对其进行迭代,则必须返回$mysqlquery,而不仅仅是一行

这是一个更好的类版本,大大改进了错误处理和安全性。但仍然糟糕的可配置性

class MySql{
    private $dbc;

    function __construct($user="root", $pass=""){
        $dsn = "mysql:host=localhost; dbname=DBNAME;charset=utf8";
        $opt = array(
           PDO::ATTR_ERRMODE            => PDO::ERRMODE_EXCEPTION,
           PDO::ATTR_DEFAULT_FETCH_MODE => PDO::FETCH_ASSOC
        );
       $this->dbc = new PDO($dsn, $user, $pass, $opt);
    }
    public function query($query, $data = array()){
        $stm = $this->dbc->prepare($query);
        $stm->execute($data);
        return $stm;
    }
}

$connection = new MySql(DBUSER, DBPASS);
$stm = $connection->query("select * from users WHERE name = ?", array("name"));
while($row = $stm->fetch()){
    echo "<p>". $row["name"] ."</p>";
}

伟大的它起作用了。我现在将安全提示应用于我的代码,并根据我的需要自定义您的代码。再次感谢。当做