Oracle 按数字分割字符串

我有这个

选择（'130.067'| |'**'）作为“赢”
来自双重

我需要在每个数字和*之间加一个空格（“”），得到这样的结果

“130.067****”

查询1：

SELECT REGEXP_REPLACE(
         '130.067'||'****', -- String to match
         '([0-9.*])',       -- Match a digit or full stop or star
         ' \1',             -- Replace with space then matched character
         2                  -- Start at the 2nd character
       ) AS win
FROM   DUAL

|                   WIN |
|-----------------------|
| 1 3 0 . 0 6 7 * * * * |

：

SELECT REGEXP_REPLACE(
         '130.067'||'****', -- String to match
         '([0-9.*])',       -- Match a digit or full stop or star
         ' \1',             -- Replace with space then matched character
         2                  -- Start at the 2nd character
       ) AS win
FROM   DUAL

|                   WIN |
|-----------------------|
| 1 3 0 . 0 6 7 * * * * |

看这里：