如果Oracle中不存在,则等同于?
以下语句适用于MSSQL:如果Oracle中不存在,则等同于?,oracle,exists,Oracle,Exists,以下语句适用于MSSQL: IF NOT EXISTS (SELECT * FROM sys.foreign_keys WHERE object_id = OBJECT_ID(N'[FK_StationObjectsID]') AND parent_object_id = OBJECT_ID(N'[Attendance]')) BEGIN ALTER TABLE Attendance ADD CONSTRAINT FK_StationObjectsID FOREIGN KEY (Stat
IF NOT EXISTS (SELECT * FROM sys.foreign_keys WHERE object_id = OBJECT_ID(N'[FK_StationObjectsID]') AND parent_object_id = OBJECT_ID(N'[Attendance]'))
BEGIN
ALTER TABLE Attendance ADD CONSTRAINT FK_StationObjectsID FOREIGN KEY (StationObjectsID) REFERENCES stationobjects (stationobjectsid)
END
在Oracle中,我尝试过:
IF NOT EXISTS (SELECT * FROM USER_CONSTRAINTS WHERE CONSTRAINT_NAME = 'FK_STATIONOBJECTSID' AND TABLE_NAME = 'ATTENDANCE') THEN
BEGIN
ALTER TABLE Attendance ADD CONSTRAINT FK_StationObjectsID FOREIGN KEY (StationObjectsID) REFERENCES stationobjects (stationobjectsid);
END;
但是它给了我一个错误PLS-00103“遇到符号‘ALTER’…”使用execute immediate在PLSQL块内触发ddl:
IF <condition> THEN
Execute immediate 'ALTER TABLE . . .';
END if;
更简单的方法是:
declare
n int := 0;
begin
select count(*) into n
from user_constraints
where constraint_name = 'FK_STATIONOBJECTSID'
and table_name = 'ATTENDANCE';
if n = 0 then
execute immediate 'ALTER TABLE Attendance ADD CONSTRAINT FK_StationObjectsID FOREIGN KEY (StationObjectsID) REFERENCES stationobjects (stationobjectsid)';
end if;
end;
/
看
-让它工作了,但可能不是最好的解决方案:
DECLARE
foreign_key_exists number := 0;
BEGIN
SELECT COUNT(*) INTO foreign_key_exists FROM USER_CONSTRAINTS WHERE upper(CONSTRAINT_NAME) = upper('FK_StationObjectsID') AND upper(TABLE_NAME) = upper('Attendance');
IF (foreign_key_exists = 0)
THEN
EXECUTE IMMEDIATE 'ALTER TABLE Attendance ADD CONSTRAINT FK_StationObjectsID FOREIGN KEY (StationObjectsID) REFERENCES stationobjects (stationobjectsid)';
END IF;
END;
/
您可以在SQL查询中使用,但不能像您尝试的那样在PLSQL条件中使用
您可能需要以下各项:
declare
vCheck number;
begin
select count(1)
into vCheck
from user_constraints
where constraint_name = 'FK_STATIONOBJECTSID'
and table_name = 'ATTENDANCE';
--
if vCheck = 0 then
execute immediate 'ALTER TABLE Attendance ADD CONSTRAINT FK_StationObjectsID FOREIGN KEY (StationObjectsID) REFERENCES stationobjects (stationobjectsid)';
end if;
end;
执行DDL并忽略任何“外键已存在”错误如何
不优雅,但不依赖于键名不变。尝试
立即执行“alter…”代码>您需要一个带有动态SQL的PL/SQL块,感谢GurV,现在得到另一个错误,即外键已经存在。好像IF有什么问题。当执行SELECT时,它返回一行,但它仍在尝试执行ALTER。。。
declare
vCheck number;
begin
select count(1)
into vCheck
from user_constraints
where constraint_name = 'FK_STATIONOBJECTSID'
and table_name = 'ATTENDANCE';
--
if vCheck = 0 then
execute immediate 'ALTER TABLE Attendance ADD CONSTRAINT FK_StationObjectsID FOREIGN KEY (StationObjectsID) REFERENCES stationobjects (stationobjectsid)';
end if;
end;