Pandas 对时间数据列执行mod函数

您好，我想将第%24列的mod函数应用于时间小时列

我相信时间列是字符串格式的

我在想我该怎么做手术

sales_id,date,time,shopping_cart,price,parcel_size,Customer_lat,Customer_long,isLoyaltyProgram,nearest_storehouse_id,nearest_storehouse,dist_to_nearest_storehouse,delivery_cost
ORD0056604,24/03/2021,45:13:45,"[('bed', 3), ('Chair', 1), ('wardrobe', 4), ('side_table', 2), ('Dining_table', 2), ('mattress', 1)]",3152.77,medium,-38.246,145.61984,1,4,Sunshine,78.43,5.8725000000000005
ORD0096594,13/12/2018,54:22:20,"[('Study_table', 4), ('wardrobe', 4), ('side_table', 1), ('Dining_table', 2), ('sofa', 4), ('Chair', 3), ('mattress', 1)]",3781.38,large,-38.15718,145.05072,1,4,Sunshine,40.09,5.8725000000000005
ORD0046310,16/02/2018,17:23:36,"[('mattress', 2), ('wardrobe', 1), ('side_table', 2), ('sofa', 1), ('Chair', 3), ('Study_table', 4)]",2219.09,medium,144.69623,-38.00731,0,2,Footscray,34.2,16.9875
ORD0031675,25/06/2018,17:38:48,"[('bed', 4), ('side_table', 1), ('Chair', 1), ('mattress', 3), ('Dining_table', 2), ('sofa', 2), ('wardrobe', 2)]",4542.1,large,144.65506,-38.40669,1,2,Footscray,72.72,18.274500000000003
ORD0019799,05/01/2021,18:37:16,"[('wardrobe', 1), ('Study_table', 3), ('sofa', 4), ('side_table', 2), ('Chair', 4), ('Dining_table', 4), ('bed', 1)]",3132.71,L,-37.66022,144.94286,1,0,Clayton,17.77,14.931
ORD0041462,25/12/2018,07:29:33,"[('Chair', 3), ('bed', 1), ('mattress', 3), ('side_table', 3), ('wardrobe', 3), ('sofa', 4)]",4416.42,medium,-38.39154,145.87448,0,6,Sunshine,105.91,6.151500000000001
ORD0047848,30/07/2021,34:18:01,"[('Chair', 3), ('bed', 3), ('wardrobe', 4)]",2541.04,small,-37.4654,144.45832,1,2,Footscray,60.85,18.4635

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通过将值转换为时间增量，然后通过索引删除天数-选择最后8个值：

print (df)
     sales_id        date      time
0  ORD0056604  24/03/2021  45:13:45
1  ORD0096594  13/12/2018  54:22:20

print (pd.to_timedelta(df['time']))
0   1 days 21:13:45
1   2 days 06:22:20
Name: time, dtype: timedelta64[ns]

df['time'] = pd.to_timedelta(df['time']).astype(str).str[-8:]

print (df)
     sales_id        date      time
0  ORD0056604  24/03/2021  21:13:45
1  ORD0096594  13/12/2018  06:22:20

如果还需要将天添加到

date

列，则解决方案是通过以下方式将时间增量添加到日期和上次提取值：

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45:13:45%24

？21:13:45，对不起，应该编辑，mod将仅应用于小时。以下代码是否适用于少于24小时的记录？我将编辑问题，请回答look@jixubi-我想是的，如果试一下会有问题吗？

dates = pd.to_datetime(df['date'], dayfirst=True) + pd.to_timedelta(df['time'])
df['time'] = dates.dt.strftime('%H:%M:%S')
df['date'] = dates.dt.strftime('%d/%m/%Y')
print (df)
     sales_id        date      time
0  ORD0056604  25/03/2021  21:13:45
1  ORD0096594  15/12/2018  06:22:20