Parsing 使用sed或awk获取标记之间的路径

我想从ps输出获取路径（/tmp/deployment/deployment/hostVBox\u 8080\u GSA/）：

username@hostVBox:~$ps ax |grep jboss
16291 pts/4    Sl     0:34 java -Dprogram.name=run.sh -Xms128m -Xmx512m -Dsun.rmi.dgc.client.gcInterval=3600000 -Dsun.rmi.dgc.server.gcInterval=3600000 -Djava.endorsed.dirs=/tmp/deployment/deployment/hostVBox_8080_GSA/lib/endorsed -classpath /tmp/deployment/deployment/hostVBox_8080_GSA/bin/run.jar:/lib/tools.jar org.jboss.Main

我该怎么做

溴 Kolesar

试试：

命令：

awk -F"dirs=" '
    /java/{
        a=$2
        split(a,path," -")
        sub(/[^/]*\/[^/]*$/,"",path[1])
        print path[1]
    }'

---

这可能适合您：

echo "a bunch of stuff ... -classpath /tmp/deployment/deployment/hostVBox_8080_GSA/bin/run.jar:/lib/tools.jar org.jboss.Main' |
sed -e 's#.*-classpath \(\([^/]*/\)*\)bin/run.jar.*#\1#'
/tmp/deployment/deployment/hostVBox_8080_GSA/

---

试试这个，看看它是否有效：

ps ax |grep jboss|awk -F'java.endorsed.dirs=' '{gsub(/lib.*/,"",$2);print $2;exit;}'