Parsing FParsec-解析器序列

假设我有一些文字：

a = "foobarbaz"
b = "foobar"
c = "foo"
d = "rubbish"
e = "foobazbar"

以及分别用于字符串“foo”、“bar”和“baz”的三个解析器foo、bar和baz

我将如何创建一个解析器来提供结果：

a = ["foo", "bar", "baz"]
b = ["foo", "bar"]
c = ["foo"]
d = []
e = ["foo"]

当针对上述输入运行时？基本上，在构建列表时，尝试每种可能性直到失败。我可以使用用户状态，但如果可能，我希望避免使用。（我想让各个解析器自己不知道用户状态）

我得到的最接近的结果如下：

let foo = pstring "foo"
let bar = pstring "bar"
let baz = pstring "baz"

let foobar = pipe2 foo bar Seq.of2
let foobarbaz = pipe3 foo bar baz Seq.of3

let fooseq = choice (Seq.map attempt [foobarbaz; foobar; foo |>> Seq.of1 ;])

//(the Seq.ofx functions just take arguments and create a sequence of them)    

---

在我看来，一定有更好的方法可以做到这一点？

FParsec没有内置的序列组合器，它完全可以满足您的要求，但您可以自己实现一个，如以下示例所示：

let mySeq (parsers: seq<Parser<'t,'u>>) : Parser<'t[],'u> =
  let ps = Array.ofSeq parsers
  if ps.Length = 0 then preturn [||]
  else
    fun stream ->   
      let mutable stateTag = stream.StateTag
      let mutable reply = ps.[0] stream
      let mutable error = reply.Error
      let mutable myReply = Reply()
      if reply.Status <> Ok then myReply.Result <- [||]
      else
        // create array to hold results
        let mutable xs = Array.zeroCreate ps.Length
        xs.[0] <- reply.Result
        let mutable i = 1
        while i < ps.Length do                    
          stateTag <- stream.StateTag
          reply <- ps.[i] stream
          error <- if stateTag <> stream.StateTag then reply.Error
                   else mergeErrors error reply.Error
          if reply.Status = Ok then
            xs.[i] <- reply.Result
            i <- i + 1
          else // truncate array and break loop         
            xs <- Array.sub xs 0 i
            i <- ps.Length 
        myReply.Result <- xs
      myReply.Status <- if reply.Status = Error && stateTag = stream.StateTag 
                        then Ok
                        else reply.Status
      myReply.Error <- error            
      myReply

let fooSeq = mySeq [foo; bar; baz]