Parsing Haskell:模式3中的分析错误
对Haskell来说比较新。想知道为什么我在尝试加载此文件后收到以下错误消息Parsing Haskell:模式3中的分析错误,parsing,haskell,design-patterns,Parsing,Haskell,Design Patterns,对Haskell来说比较新。想知道为什么我在尝试加载此文件后收到以下错误消息 data Peg = Red | Green | Blue | Yellow | Orange | Purple deriving (Show, Eq, Ord) type Code = [Peg] data Move = Move Code Int Int deriving (Show, Eq) isConsistent :: Move -> Code -> Bool isCon
data Peg = Red | Green | Blue | Yellow | Orange | Purple
deriving (Show, Eq, Ord)
type Code = [Peg]
data Move = Move Code Int Int
deriving (Show, Eq)
isConsistent :: Move -> Code -> Bool
isConsistent (move1 code1 num1 num2) code2 = True --parse error here
move1
不是数据构造函数(这是允许模式匹配的),事实上也不是,因为它们必须以大写字母开头。将其替换为数据声明中的构造函数Move
,错误就会消失
您可能仍然会收到一些警告,如“code1已定义但未使用”,如果您真的不关心内容,您可以通过将模式更改为
(Move\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu@(移动代码int1 int2)
move1
现在指的是整个移动。
Parse error in pattern: move1