CakePHP 3-使用多个条件查找
我正在尝试进行查询,以查找具有特定集合或ID的所有行 例如,我想查找具有以下值之一的device_id字段的all: 1. 3. 五, 我尝试将其添加为数组,但出现以下错误: 无法将值转换为整数 这是我的密码:CakePHP 3-使用多个条件查找,php,cakephp,cakephp-3.0,Php,Cakephp,Cakephp 3.0,我正在尝试进行查询,以查找具有特定集合或ID的所有行 例如,我想查找具有以下值之一的device_id字段的all: 1. 3. 五, 我尝试将其添加为数组,但出现以下错误: 无法将值转换为整数 这是我的密码: $revenuesQuery = $revenues->find('all', [ 'conditions' => [ 'device_id' => [1, 3, 5], 'date' => date
$revenuesQuery = $revenues->find('all', [
'conditions' => [
'device_id' => [1, 3, 5],
'date' => date('Y-m-d')
]
]);
如您所见,设备_id是一个整数数组(3和4),我不希望有其中一个(3或4)的行。如果我将代码更改为不使用数组,而是使用如下硬整数:
$revenuesQuery = $revenues->find('all', [
'conditions' => [
'device_id' => 3,
'date' => date('Y-m-d')
]
]);
它工作正常吗
以下是我的已调试查询:
'(help)' => 'This is a Query object, to get the results execute or iterate it.',
'sql' => 'SELECT Revenues.id AS `Revenues__id`, Revenues.device_id AS `Revenues__device_id`, Revenues.revenue AS `Revenues__revenue`, Revenues.date AS `Revenues__date` FROM revenues Revenues WHERE (device_id = :c0 AND date = :c1)',
'params' => [
':c0' => [
'value' => [
(int) 0 => (int) 3,
(int) 1 => (int) 4
],
'type' => 'integer',
'placeholder' => 'c0'
],
':c1' => [
'value' => '2017-12-17',
'type' => 'date',
'placeholder' => 'c1'
]
]
提前谢谢。您要找的东西叫做 将中的
一词添加到字段名称的末尾
$revenuesQuery = $revenues->find('all', [
'conditions' => [
'device_id IN' => [1, 3, 5],
'date' => date('Y-m-d')
]
]);
或者,查询表达式生成器更详细,这是我在CakePHP中创建查询的首选方法
$q = $revenues->query();
$revenuesQuery = $revenues->find('all')
->where([
$q->newExp()->in('device_id', [1, 3, 5]),
$q->newExp()->eq('date', $q->func()->now())
]);
请看Cake 3的查询生成器:
您可以执行以下操作:
$devIds = [1,2,3];
$revenuesQuery = $this->revenues->find()
->where(function (QueryExpression $exp) use ($devIds) {
return $exp
->in('device_id', $devIds)
->eq('date', q->func()->now() );
});
第二种选择更符合Cake3的要点。第一个解决方案要求记住Sql,这与ORM概念相矛盾。