Cakephp修改联接查询以添加计数，而不是获取表的所有详细信息

我试图得到最近10个视频连同他们的总看法和喜欢，如果我喜欢或不喜欢的视频

这是我的密码

 $videos = $this->Video->find('all', array(
                        'joins' => array(
                                array(
                                    'table' => 'video_views',
                                    'alias' => 'views',
                                    'type' =>  'INNER',
                                    'conditions' => array(
                                        'views.userId = Video.id',                                        
                                    )
                                ),
                                array(
                                    'table' => 'video_likes',
                                    'alias' => 'likes',
                                    'type' =>  'INNER',
                                    'conditions' => array(
                                        'likes.userId = Video.id',                                        
                                    )
                                )
                        ),
                        'fields' => array('Video.*'),            
                        'order' => array('Video.creationDate DESC'),
                        'limit' => 10,
                        'offset' => $offset * 10
                ));

目前，它正在获得10个最新视频、他们的喜好数据和浏览数据

但是，我希望修改查询以获得count（*），而不是合并所有视图/数据

类似视频['ViewScont']=xxx的东西

第二，我想从喜欢表中知道我是否喜欢那个特定的视频

如何修改此查询

感谢@newbeeDev

$videos = $this->Video->find('all', array(
                'fields' => array(
                        'Video.*',
                        'Count(View.id) as views',
                        'Count(Like.id) as likes',
                        '(CASE when Liked.id is not null then 1 else 0 end) as liked'
                ),
                'joins' => array(
                        array(
                                'type' => 'LEFT',
                                'table' => 'video_views',
                                'alias' => 'View',
                                'conditions' => array('Video.id = View.videoId')
                        ),                          
                        array(
                                    'type' => 'LEFT',
                                    'table' => 'video_likes',
                                    'alias' => 'Like',
                                    'conditions' => array('Video.id = Like.videoId')
                            ),
                        array(
                                'type' => 'LEFT',
                                'table' => 'video_likes',
                                'alias' => 'Liked',
                                'conditions' => array('Video.id = Liked.videoId AND Liked.userId = ' . $userId)
                        ),
                ),
                'group' => array(
                        'Video.id'
                ),
                'order' => array('Video.creationDate DESC'),
                'limit' => 10,
                'offset' => $offset * 10
        ));

只需将连接替换为

    'joins' => array(
            array(
                    'table' => 'video_views',
                    'alias' => 'View',
                    'conditions' => array('Video.id = View.video_id')
            ),
            array(
                    'type' => 'LEFT',
                    'table' => 'video_likes',
                    'alias' => 'Like',
                    'conditions' => array('Video.id = Like.video_id and Like.user_id = 1')
            ),
    ),

您的查询生成器如下所示

         $videos = $this->Video->find('all', array(
            'fields' => array(
                    'Video.*',
                    'Count(View.id) as views',
                    '(CASE when Like.id is not null then 1 else 0 end) as liked'
            ),
            'joins' => array(
                    array(
                            'table' => 'video_views',
                            'alias' => 'View',
                            'conditions' => array('Video.id = View.video_id')
                    ),
                    array(
                            'type' => 'LEFT',
                            'table' => 'video_likes',
                            'alias' => 'Like',
                            'conditions' => array('Video.id = Like.video_id and Like.user_id = 1')
                    ),
            ),
            'group' => array(
                    'Video.id'
            ),
            'order' => array('Video.creationDate DESC'),
            'limit' => 10,
            'offset' => $offset * 10
    ));

---

您想要的查询结果到底是什么？把它包括在你的计划中post@NewbeeDev需要添加视频['likescont']=xxx，而不是当前正在进行的视频['likes']=array（），它工作得很好，但是如果视频没有任何喜欢的内容或视图，它就不会显示that@MuhammadUmar只需在加入中添加“type”=>“left”，它不会显示，因为join单独需要匹配项，但使用left join，即使没有匹配项，它也会显示