Php 如何通过指定的日期范围来判断季节

我将根据给定的日期指定季节。我有4个季节，按日期（不是按月份）排列。所以我决定在数组中使用

和
range（）
，但它没有显示任何内容

这是我的密码：

$p1=strtotime("2013-12-13");
$p2=strtotime("2014-02-20");
$h1a=strtotime("2014-02-21");
$h1b=strtotime("2014-04-31");
$l1=strtotime("2013-05-01");
$l2=strtotime("2013-10-31");
$h2a=strtotime("2013-11-01");
$h2b=strtotime("2013-12-19");


$today=strtotime(date("Y-m-d"));

if(in_array($today, range($p1, $p2))){
    echo "peak";
}elseif(in_array($today, range($h1a, $h1b))){
    echo "hi1";
}elseif(in_array($today, range($l1, $l2))){
    echo "low";
}else(in_array($today, range($h2a, $h2b))){
    echo "h2";
}

你们能改进我的代码吗

关于，
，因为您的内存限制超出了范围。我只用了2天的时间，它显示了大部分的输出

可以使用大于和小于来度量日期

if($today >= $p1 && $today <= $p2){
    echo "peak";
}elseif($today >= $h1a && $today <= $h1b){
    echo "hi1";
}elseif($today >= $l1 && $today <= $l2){
    echo "low";
}else($today >= $h2a && $today <= $h2b){
    echo "h2";
}

如果（$today>=$p1&&$today=$h1a&&&$today=$l1&&$today=$h2a&&$today我现在有了自己的解决方案。感谢这些试验。代码改编自：

因为您的内存限制超出了范围。我只在范围内使用了2天，它显示了大部分输出。有没有更好的方法来测试季节的当前日期？请参阅大于和小于的答案。Yogesh，您的代码看起来更好，但不起作用。它不会返回“低”如我所料。@Wilf将看到编辑过的答案。只是使用了错误顺序的比较。：）
<?
function current_season() {
       // Locate the icons
       $icons = array(
               "peak" => "peak season",
               "low" => "low season",
               "high1" => "high1 season",
               "high2" => "high2 season"
       );

       // What is today's date - number
       $day = date("z");

       //  Days of peak
       $peak_starts = date("z", strtotime("December 13"));
       $peak_ends   = date("z", strtotime("February 20"));

       //  Days of low
       $low_starts = date("z", strtotime("May 1"));
       $low_ends   = date("z", strtotime("October 31"));

       //  Days of high
       $high_starts = date("z", strtotime("February 21"));
       $high_ends   = date("z", strtotime("April 31"));

       //  If $day is between the days of peak, low, high, and winter
       if( $day >= $peak_starts && $day <= $peak_ends ) :
               $season = "peak";
       elseif( $day >= $low_starts && $day <= $low_ends ) :
               $season = "low";
       elseif( $day >= $high1_starts && $day <= $high1_ends ) :
               $season = "high";
       else :
               $season = "high2";
       endif;

       $image_path = $icons[$season];

       echo $image_path;
}
echo current_season();
?>