Php 如何根据用户的状态和角色登录用户

我正在创建一个登录页面，用户和管理员将在其中登录 在管理员将其激活之前，用户的角色为user，状态为pending。 我有不同的文件显示为用户和管理员，在用户，有2个文件。1用于活动用户，另一个用于挂起用户

我创建了if语句并尝试了switch语句。但我在XAMPP“解析错误：语法错误，C:\XAMPP\htdocs\MakerLab\server.php中文件的意外结尾，第109行”上遇到了一个错误

这是我的server.php

---

下次您可以使用类似于IDE的PHPStorm来帮助缩进和格式时，文件末尾（在？>标记之前）缺少2个括号

<?php

// variable declaration
$email = "";
$status = "";

$errors = array();
$_SESSION['success'] = "";

// connect to database
$db = mysqli_connect('localhost', 'root', '', 'makerlab');

// REGISTER USER
if (isset($_POST['reg_user'])) {
    // receive all input values from the form
    $fname = mysqli_real_escape_string($db, $_POST['fname']);
    $lname = mysqli_real_escape_string($db, $_POST['lname']);
    $email = mysqli_real_escape_string($db, $_POST['email']);
    $lewisID = mysqli_real_escape_string($db, $_POST['lewisID']);
    $password_1 = mysqli_real_escape_string($db, $_POST['password_1']);
    $password_2 = mysqli_real_escape_string($db, $_POST['password_2']);

    // form validation: ensure that the form is correctly filled
    //if (empty($email)) { array_push($errors, "Lewis Email is required"); }
    //if (empty($password_1)) { array_push($errors, "Password is required"); }

    //if ($password_1 != $password_2) {
    //  array_push($errors, "The two passwords do not match");
    //}

    $user_check_query = "SELECT * FROM users WHERE lewisID='$lewisID' OR email='$email' LIMIT 1";
    $result = mysqli_query($db, $user_check_query);
    $user = mysqli_fetch_assoc($result);

    if ($user) { // if user exists
        if ($user['lewisID'] === $lewisID) {
            array_push($errors, "lewisID already exists");
        }

        if ($user['email'] === $email) {
            array_push($errors, "lewisID already exists");
        }
    }

    // register user if there are no errors in the form
    if (count($errors) == 0) {
        $password = md5($password_1);//encrypt the password before saving in the database
        $query = "INSERT INTO users (lewisID,
                                    fname, 
                                    lname, 
                                    email, 
                                    password) 
                    VALUES('$lewisID',
                            '$fname', 
                            '$lname', 
                            '$email',
                            '$password')";
        mysqli_query($db, $query);
        $_SESSION['fname'] = $fname;
        $_SESSION['email'] = $email;
        header('location: pend.php');
    }
}

// ...

// LOGIN USER
if (isset($_POST['login_user'])) {
    $email = mysqli_real_escape_string($db, $_POST['email']);
    $password = mysqli_real_escape_string($db, $_POST['password']);

    if (empty($email)) {
        array_push($errors, "Lewis Email is required");
    }
    if (empty($password)) {
        array_push($errors, "Password is required");
    }

    if (count($errors) == 0) {
        $password = md5($password);
        $query = "SELECT * FROM users WHERE email='$email' 
        AND password='$password'";

        $results = mysqli_query($db, $query);

        if (mysqli_num_rows($results) == 1) {
            $_SESSION['email'] = $email;
            $row = mysqli_fetch_assoc($results);
            $status = $row['status'];
            $role = $row['role'];
            if ($status == "Pending") {
                header('location: pend.php');
            } else if ($status == "Active" || $role == "user") {
                header('location: AccountMain.php');
            } else if ($status == "Active" || $role == "admin") {
                header('location: admain.php');
            }
        } else {
            array_push($errors, "Wrong username/password combination");
        }
    }
}
?>

下次您可以使用类似于IDE的PHPStorm来帮助缩进和格式时，文件末尾（在？>标记之前）缺少2个括号

<?php

// variable declaration
$email = "";
$status = "";

$errors = array();
$_SESSION['success'] = "";

// connect to database
$db = mysqli_connect('localhost', 'root', '', 'makerlab');

// REGISTER USER
if (isset($_POST['reg_user'])) {
    // receive all input values from the form
    $fname = mysqli_real_escape_string($db, $_POST['fname']);
    $lname = mysqli_real_escape_string($db, $_POST['lname']);
    $email = mysqli_real_escape_string($db, $_POST['email']);
    $lewisID = mysqli_real_escape_string($db, $_POST['lewisID']);
    $password_1 = mysqli_real_escape_string($db, $_POST['password_1']);
    $password_2 = mysqli_real_escape_string($db, $_POST['password_2']);

    // form validation: ensure that the form is correctly filled
    //if (empty($email)) { array_push($errors, "Lewis Email is required"); }
    //if (empty($password_1)) { array_push($errors, "Password is required"); }

    //if ($password_1 != $password_2) {
    //  array_push($errors, "The two passwords do not match");
    //}

    $user_check_query = "SELECT * FROM users WHERE lewisID='$lewisID' OR email='$email' LIMIT 1";
    $result = mysqli_query($db, $user_check_query);
    $user = mysqli_fetch_assoc($result);

    if ($user) { // if user exists
        if ($user['lewisID'] === $lewisID) {
            array_push($errors, "lewisID already exists");
        }

        if ($user['email'] === $email) {
            array_push($errors, "lewisID already exists");
        }
    }

    // register user if there are no errors in the form
    if (count($errors) == 0) {
        $password = md5($password_1);//encrypt the password before saving in the database
        $query = "INSERT INTO users (lewisID,
                                    fname, 
                                    lname, 
                                    email, 
                                    password) 
                    VALUES('$lewisID',
                            '$fname', 
                            '$lname', 
                            '$email',
                            '$password')";
        mysqli_query($db, $query);
        $_SESSION['fname'] = $fname;
        $_SESSION['email'] = $email;
        header('location: pend.php');
    }
}

// ...

// LOGIN USER
if (isset($_POST['login_user'])) {
    $email = mysqli_real_escape_string($db, $_POST['email']);
    $password = mysqli_real_escape_string($db, $_POST['password']);

    if (empty($email)) {
        array_push($errors, "Lewis Email is required");
    }
    if (empty($password)) {
        array_push($errors, "Password is required");
    }

    if (count($errors) == 0) {
        $password = md5($password);
        $query = "SELECT * FROM users WHERE email='$email' 
        AND password='$password'";

        $results = mysqli_query($db, $query);

        if (mysqli_num_rows($results) == 1) {
            $_SESSION['email'] = $email;
            $row = mysqli_fetch_assoc($results);
            $status = $row['status'];
            $role = $row['role'];
            if ($status == "Pending") {
                header('location: pend.php');
            } else if ($status == "Active" || $role == "user") {
                header('location: AccountMain.php');
            } else if ($status == "Active" || $role == "admin") {
                header('location: admain.php');
            }
        } else {
            array_push($errors, "Wrong username/password combination");
        }
    }
}
?>

请注意您易受攻击，并应使用以防止此情况发生。除此之外，
md5（）
是（即使有盐），不应用于密码存储。相反，你应该考虑和谢谢。我下一步会做的。我需要if语句方面的帮助您的错误似乎也是由于缺少一个
}
（对于
if（count（$errors）==0）
）；使用适当的缩进可以更容易地确认这一点。一些用于编写代码的程序，例如，如果单击{它将向您显示它认为匹配的}的位置。我正在使用记事本+，它确实显示了所有匹配项，但我添加了2个括号，需要，但现在抱怨第89-92-94行的角色未定义。请注意，您很容易受到攻击，应该使用它来防止出现这种情况。除此之外，
md5（）
是（即使有盐），不应用于密码存储。相反，你应该考虑和谢谢。我下一步会做的。我需要if语句方面的帮助您的错误似乎也是由于缺少一个
}
（对于
if（count（$errors）==0）
）；使用适当的缩进可以更容易地确认这一点。一些用于编写代码的程序，例如，如果单击{它将向您显示它认为匹配的}的位置。我使用的是记事本+，它确实显示了所有匹配项，但我添加了两个括号，需要花费时间，但现在抱怨第89-92行的角色未定义，谢谢，@Elminson De Oleo Baez。我添加了他们，它带来了网站，但现在我无法登录。我尝试与一个活跃的和挂起的用户，它没有做任何事情。请让我回到登录页面问题是您的登录用户部分在注册用户中，我将编辑我的答案，然后您可以再次测试。您现在可以使用新代码@Zaheemhasantanks进行测试。我试过了，但现在它抱怨角色变量没有定义。我的数据库名称“role”中有一列您的问题是您正在访问变量
$role
，该变量未定义
$row['role']=$role因此您必须将其转换为
$role=$row['role']谢谢，@Elminson De Oleo Baez。我添加了他们，它带来了网站，但现在我无法登录。我尝试与一个活跃的和挂起的用户，它没有做任何事情。请让我回到登录页面问题是您的登录用户部分在注册用户中，我将编辑我的答案，然后您可以再次测试。您现在可以使用新代码@Zaheemhasantanks进行测试。我试过了，但现在它抱怨角色变量没有定义。我的数据库名称“role”中有一列您的问题是您正在访问变量
$role
，该变量未定义
$row['role']=$role因此您必须将其转换为
$role=$row['role']