Php Json编码自动完成源代码

我通常有这样的数组

(int) 0 => abc,
(int) 1 => def,
(int) 2 => ghi

var company = [
  {
    value: "jquery",
    label: "jQuery",
    name: "the write less, do more, JavaScript library",
    address: "jquery_32x32.png",
    city: "xxxxx",
  },
  {
    value: "jquery-ui",
    label: "jQuery UI",
    name: "the write less, do more, JavaScript library",
    address: "jquery_32x32.png",
    city: "xxxxx",
  },
  {
    value: "sizzlejs",
    label: "Sizzle JS",
    name: "the write less, do more, JavaScript library",
    address: "jquery_32x32.png",
    city: "xxxxx",
  }
];

array(
    (int) 0 => array(
        'Company' => array(
            'id' => '19',
            'group_id' => '1',
            'name' => 'Harts Harts',
            'address' => 'xxx NE xxxth Street',
            'city' => 'Shoreline',
            'state' => 'WA',
            'zip' => '98155',
            'country' => '',
        )
    ),
    (int) 1 => array(
        'Company' => array(
            'id' => '21',
            'group_id' => '1',
            'name' => 'Andy Robin',
            'address' => 'xxx xxxth Ave NE',
            'city' => 'Bellevue',
            'state' => 'WA',
            'zip' => '98004',
            'country' => '',
        )
    )
)

如果我使用json_编码，它将变成

["abc", "def", "ghi"]

这对于jquery自动完成非常有用

$(function() {
    var availableTags = <?php echo json_encode($companyList); ?>;
    $("#CompanyName").autocomplete({
        source: availableTags,
        delay: 10
    });
}); 

如何进行json_编码（或任何其他方式）来更改这样的PHP数组

(int) 0 => abc,
(int) 1 => def,
(int) 2 => ghi

var company = [
  {
    value: "jquery",
    label: "jQuery",
    name: "the write less, do more, JavaScript library",
    address: "jquery_32x32.png",
    city: "xxxxx",
  },
  {
    value: "jquery-ui",
    label: "jQuery UI",
    name: "the write less, do more, JavaScript library",
    address: "jquery_32x32.png",
    city: "xxxxx",
  },
  {
    value: "sizzlejs",
    label: "Sizzle JS",
    name: "the write less, do more, JavaScript library",
    address: "jquery_32x32.png",
    city: "xxxxx",
  }
];

array(
    (int) 0 => array(
        'Company' => array(
            'id' => '19',
            'group_id' => '1',
            'name' => 'Harts Harts',
            'address' => 'xxx NE xxxth Street',
            'city' => 'Shoreline',
            'state' => 'WA',
            'zip' => '98155',
            'country' => '',
        )
    ),
    (int) 1 => array(
        'Company' => array(
            'id' => '21',
            'group_id' => '1',
            'name' => 'Andy Robin',
            'address' => 'xxx xxxth Ave NE',
            'city' => 'Bellevue',
            'state' => 'WA',
            'zip' => '98004',
            'country' => '',
        )
    )
)

类似于jquery的autocomplete源代码，因为如果我直接使用json_encode（$company），它将成为对象，而我不能将其用于autocomplete

这个阵列将有大约2500个数据

---

谢谢

使用jQuery parseJSON方法解析从PHP获得的json

var obj = jQuery.parseJSON( 'json_string_here' );

输出：

[{"id":"19","group_id":"1","name":"Harts Harts","address":"xxx NE xxxth Street","city":"Shoreline","state":"WA","zip":"98155","country":""},{"id":"21","group_id":"1","name":"Andy Robin","address":"xxx xxxth Ave NE","city":"Bellevue","state":"WA","zip":"98004","country":""}]

注意：要用于jquery自动完成，您需要在返回的

json

中添加

值

或

标签

字段。您当前没有这两个字段。

api jquery ui:

阅读自动完成api后：

$companyList = array();
foreach($companies as $company){
    array_push( $companyList, $company["Company"]["name"]);
}

返回：

["Harts Harts","Andy Robin"]

autocomplete将使用此计划旧数组或对象属性数组

标签

和

值

，如下所示：

[{label:"Harts Harts",value:"Harts Harts"},{label:"Andy Robin",value:"Andy Robin"}]

---

如果你还有什么问题，就问吧

这样一来，我觉得它会因为大量的数据（2500个数据）而导致问题。翻页时速度会很慢loading@Hart我使用了与美国邮政编码相同的代码，一次提取数千个邮政编码，但如果页面上运行了其他内容，则可能是这样。@Harts如果您是从automcompete的数据库提取邮政编码，您可以在此处使用我的示例：