Php 在Google analytics中实施像素跟踪以跟踪未结利率

我正在学习教程：

$var_utmac = 'UA-29940706-1'; //enter the new urchin code
$var_utmhn = 'mywebsite.com'; //enter your domain
$var_utmn = rand(1000000000,9999999999); //random request number
$var_cookie = rand(10000000,99999999); //random cookie number
$var_random = rand(1000000000,2147483647); //number under 2147483647
$var_today = time(); //today
$utm_source = 'newsletter';
$utm_medium = 'email';
$utm_campaign = 'newsletter111';
$var_uservar = '-'; //enter your own user defined variable
$var_utmp = 'http://dl.dropbox.com/u/15672207/web.png'; //this example adds a fake file request to the (fake) tracker directory (the image/pdf filename).
$urchinUrl = 'http://www.google-analytics.com/__utm.gif?utmwv=1&utmn='.$var_utmn.'&utmsr=-&utmsc=-&utmul=-&utmje=0&utmfl=-&utmdt=-&utmhn='.$var_utmhn.'&utm_source='.$utm_source.'&utm_medium='.$utm_medium.'&utm_campaign='.$utm_campaign.'&utmp='.$var_utmp.'&utmac='.$var_utmac.'&utmcc=__utma%3D'.$var_cookie.'.'.$var_random.'.'.$var_today.'.'.$var_today.'.'.$var_today.'.2%3B%2B__utmb%3D'.$var_cookie.'%3B%2B__utmc%3D'.$var_cookie.'%3B%2B__utmz%3D'.$var_cookie.'.'.$var_today.'.2.2.utmccn%3D(direct)%7Cutmcsr%3D(direct)%7Cutmcmd%3D(none)%3B%2B__utmv%3D'.$var_cookie.'.'.$var_uservar.'%3B';

// Now fire off the HTTP request
$handle = fopen ($urchinUrl, "r");
$test = fgets($handle);
fclose($handle);

// Redirect this script as an actual GIF file sitting on this web server
header('Location: http://dl.dropbox.com/u/15672207/web.png');

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我现在可以在Google Analytics中跟踪此脚本的打开率。但这是否意味着我只能在一次活动中拥有一个谷歌分析账户？那么它真的需要一天的时间来收集数据吗？

请不要重复你自己的问题：

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如果您的推理是在几个线程之间进行的，我们无法给您答复…

有趣的是，我看到有人使用了该代码。请帮助我解决一些问题我可以简单地说，好的，1个问题解决了对不起，因为问题的类型不同，但它是在同一个主题上