Php MySQL Union all与MySQL内部联接相结合

我想从

allinventory\u tb

获取描述和模型

所以我做了内部连接，但当我要显示描述和模型时

错误如下：

$sql = "select t.itemcode  as itemcode ,sum(t.qty) as qty
    from ( 
    select itemcode,qty  from barcode INNER JOIN allinventory_tb on barcode.itemcode = allinventory_tb.in_code
    union all
    select itemcode,qty from adjustment_tb INNER JOIN allinventory_tb on adjustment_tb.itemcode = allinventory_tb.in_code where adjustment_tb.status='APPROVED'
    union all
    select itemcode,(qty * -1) from soldout_pd INNER JOIN allinventory_tb on soldout_pd.itemcode = allinventory_tb.in_code) as t
    group by itemcode";


    $result = $conn->query($sql);

注意：未定义索引：描述，注意：未定义索引：模型

有什么建议吗

  |allinventory_tb|
  ----------------
  |in_code        |
  |description    |
  |model          |
  ---------------
    $sql = "select t.itemcode  as itemcode ,sum(t.qty) as qty
    from ( 
    select itemcode,qty  from barcode INNER JOIN allinventory_tb on barcode.itemcode = allinventory_tb.in_code
    union all
    select itemcode,qty from adjustment_tb INNER JOIN allinventory_tb on adjustment_tb.itemcode = allinventory_tb.in_code where adjustment_tb.status='APPROVED'
    union all
    select itemcode,(qty * -1) from soldout_pd INNER JOIN allinventory_tb on soldout_pd.itemcode = allinventory_tb.in_code) as t
    group by itemcode";

    $result = $conn->query($sql);

---

使用您的查询，即

$sql = "select t.itemcode  as itemcode ,sum(t.qty) as qty
    from ( 
    select itemcode,qty  from barcode INNER JOIN allinventory_tb on barcode.itemcode = allinventory_tb.in_code
    union all
    select itemcode,qty from adjustment_tb INNER JOIN allinventory_tb on adjustment_tb.itemcode = allinventory_tb.in_code where adjustment_tb.status='APPROVED'
    union all
    select itemcode,(qty * -1) from soldout_pd INNER JOIN allinventory_tb on soldout_pd.itemcode = allinventory_tb.in_code) as t
    group by itemcode";


    $result = $conn->query($sql);

您将无法访问描述和模型列值，因为您没有在查询中指定所需的列名，所以当您尝试在PHP中访问查询结果时，您将收到如下错误通知：

注意：未定义索引：描述，注意：未定义索引：模型

尝试此查询

$sql = "select description,model,t.itemcode  as itemcode ,sum(t.qty) as qty
    from ( 
    select description,model,itemcode,qty  from barcode as bc INNER JOIN allinventory_tb as ait on bc.itemcode = ait.in_code
    union all
    select description,model,itemcode,qty from adjustment_tb as adt INNER JOIN allinventory_tb as ait1 on adt.itemcode = ait1.in_code where adjustment_tb.status='APPROVED'
    union all
    select description,model,itemcode,(qty * -1) from soldout_pd as slp INNER JOIN allinventory_tb as ait2 on slp.itemcode = ait2.in_code) as t
    group by itemcode";


$result = $conn->query($sql);

---

希望这对您有用…

您的错误看起来像是来自PHP而不是MySQL。原始查询在MySQL中运行时是否没有错误？控制台会给你什么错误？查询正在运行，没有错误，如果我要在allinvty_tb中显示该行，则会显示错误，尽管我已经做了内部联接。你能否始终引用表名？仅在您的问题中，我就看到了该名称的三个版本：

allinventory\u tb

、

allinvty3

和

allinvty\u tb

。抱歉。我的代码已经更新。注意：正在尝试获取非对象的属性。我已经检查过了。@codeSeven你能根据上面的查询发布你的var_dump（）结果吗。我认为您访问它是错误的。我同意@FaisalMohm，请发布您的var_dump（）结果