将postgresql间隔格式转换为php中可用的格式

我在PHP中有一个函数，它以以下格式返回从postgresql数据库经过的时间

00:34:01.024416

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在php中，这些数据以“字符串”的形式存储，这没有多大用处。我可以在PHP中使用什么来计算数据库提供的数据？

您可以将postgres中的数据转换为毫秒或微秒。这可以存储在PHP中，稍后用于操作所花费的总时间。。。下面这样的查询将在这方面帮助您

SELECT
(EXTRACT (HOURS FROM TIME '00:34:01.024416') * 3600000) :: int AS "hour-millisecond",
(EXTRACT (MINUTE FROM TIME '00:34:01.024416') * 60000) :: int AS "minute-millisecond",
(EXTRACT (SECOND FROM TIME '00:34:01.024416') * 1000) :: int AS "second-millisecond",
(EXTRACT (MILLISECONDS FROM TIME '00:34:01.024416')) :: int AS "millisecond"

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[编辑]

SELECT (EXTRACT (HOURS FROM  elapsedtime_result.elapsedtime) * 3600000) :: int + 
(EXTRACT (MINUTE FROM  elapsedtime_result.elapsedtime) * 60000) :: int + 
(EXTRACT (SECOND FROM  elapsedtime_result.elapsedtime) * 1000) :: int + 
(EXTRACT (MILLISECONDS FROM  elapsedtime_result.elapsedtime)) :: int AS millisecondelapsed 
FROM (SELECT current_timestamp - max(createdon) elapsedtime FROM testtable) AS elapsedtime_result

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把它转换成总的微秒数怎么样？@NandakumarV你能给我举个例子说明如何用PHP来实现吗？我来自Java背景，没有PHPIs方面的经验，在查询中使用select语句，而不是静态地给出时间？因此，在“00:34:01.024416”中没有返回interval的查询。

SELECT (EXTRACT (HOURS FROM  elapsedtime_result.elapsedtime) * 3600000) :: int + 
(EXTRACT (MINUTE FROM  elapsedtime_result.elapsedtime) * 60000) :: int + 
(EXTRACT (SECOND FROM  elapsedtime_result.elapsedtime) * 1000) :: int + 
(EXTRACT (MILLISECONDS FROM  elapsedtime_result.elapsedtime)) :: int AS millisecondelapsed 
FROM (SELECT current_timestamp - max(createdon) elapsedtime FROM testtable) AS elapsedtime_result