Php 警告:PDOStatement::execute():SQLSTATE[HY093]:无效参数编号:绑定变量的数量与中的令牌数量不匹配
我正在使用PHP PDO,我有以下问题:Php 警告:PDOStatement::execute():SQLSTATE[HY093]:无效参数编号:绑定变量的数量与中的令牌数量不匹配,php,database,data-binding,code-snippets,Php,Database,Data Binding,Code Snippets,我正在使用PHP PDO,我有以下问题: Warning: PDOStatement::execute(): SQLSTATE[HY093]: Invalid parameter number: number of bound variables does not match number of tokens in /var/www/site/classes/enterprise.php on line 63 这是我的密码: public function getCompaniesBy
Warning: PDOStatement::execute(): SQLSTATE[HY093]: Invalid parameter number: number of bound variables does not match number of tokens in /var/www/site/classes/enterprise.php on line 63
这是我的密码:
public function getCompaniesByCity(City $city, $options = null) {
$database = Connection::getConnection();
if(empty($options)) {
$statement = $database->prepare("SELECT * FROM `empresas` WHERE `empresas`.`cidades_codigo` = ?");
$statement->bindValue(1, $city->getId());
}
else {
$sql = "SELECT * FROM `empresas`
INNER JOIN `prods_empresas` ON `prods_empresas`.`empresas_codigo` = `empresas`.`codigo` WHERE ";
foreach($options as $option) {
$sql .= '`prods_empresas`.`produtos_codigo` = ? OR ';
}
$sql = substr($sql, 0, -4);
$sql .= ' AND `empresas`.`cidades_codigo` = ?';
$statement = $database->prepare($sql);
echo $sql;
foreach($options as $i => $option) {
$statement->bindValue($i + 1, $option->getId());
}
$statement->bindValue(count($options), $city->getId());
}
$statement->execute();
$objects = $statement->fetchAll(PDO::FETCH_OBJ);
$companies = array();
if(!empty($objects)) {
foreach($objects as $object) {
$data = array(
'id' => $object->codigo,
'name' => $object->nome,
'link' => $object->link,
'email' => $object->email,
'details' => $object->detalhes,
'logo' => $object->logo
);
$enterprise = new Enterprise($data);
array_push($companies, $enterprise);
}
return $companies;
}
}
由于您已在循环中生成了
$i+1
,因此计数($options)
将等于生成重复绑定的最后一个$i+1
。请尝试
foreach($options as $i => $option)
{
$statement->bindValue($i + 1, $option->getId());
}
$statement->bindValue(count($options)+1, $city->getId());
看起来您正在尝试构建一个长(?)系列的“或”比较:
如果(x=1)或(x=2)或(x=3)等…
。您可能会发现更容易将其替换为:
$cnt = count($options);
if ($cnt > 0) {
$placeholders = str_repeat(', ?', $cnt - 1);
$sql .= 'WHERE '`prods_empresas`.`produtos_codigo` IN (?' . $placeholders . ')';
}
如果有5个选项,你会得到
WHERE prods_empresas.produtos_condigo IN (?, ?, ?, ?, ?)
然后将值绑定到:
$pos = 1;
foreach ($options as $option) {
$statement->bindValue($pos, $option->getId());
$pos++
}
绑定参数的数量与SQL中的绑定数量不匹配。仔细检查
?
的数量和绑定参数的数量是否相同
此外,如果您试图绑定一个不存在的参数,HY093
将显示:
$stmt = "INSERT INTO table VALUES (:some_value)";
$stmt->bindValue(':someValue', $someValue, PDO::PARAM_STR);
查看:some_值
与:some值
不匹配!解决办法是:
$stmt = "INSERT INTO table VALUES (:some_value)";
$stmt->bindValue(':some_value', $someValue, PDO::PARAM_STR);
SQL中的位置参数从1开始。您通过绑定到$options循环中的位置
$i+1
来处理此问题
但随后将cidades_codigo
的最后一个参数绑定到位置count($options)
,这将覆盖$options循环中设置的最后一个参数
您需要将最后一个参数绑定到位置count($options)+1
FWIW,您根本不需要
bindValue()
。只需将一组参数传递给execute()
就更容易了。下面是我编写此函数的方法:
public function getCompaniesByCity(City $city, $options = null) {
$database = Connection::getConnection();
$sql = "SELECT * FROM `empresas` WHERE `empresas`.`cidades_codigo` = ?"
$params = array();
$params[] = $city->getId();
if ($options) {
$sql .= " AND `prods_empresas`.`produtos_codigo` IN ("
. join(",", array_fill(1, count($options), "?") . ")";
foreach ((array)$options as $option) {
$params[] = $option->getId();
}
}
$statement = $database->prepare($sql);
echo $sql;
$statement->execute($params);
. . .
还要确保检查
prepare()
和execute()
的返回值,如果有错误,它将是false
,您需要检查并报告错误。或者启用PDO在出错时抛出异常。我遇到了这个问题,因为在命名参数映射数组中有额外的条目传递给PDO::Statement->execute()
我不明白这是一个答案还是一个评论。请你重新措辞好吗?
$args=array (":x" => 17 );
$pdo->prepare("insert into foo (x) values (:x)");
$pdo->execute($args); // success
$args[':irrelevant']=23;
$pdo->execute($args) // throws exception with HY093